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xz_007 [3.2K]
3 years ago
5

Find three consecutive odd integers such that the first is 33 less than twice the second

Mathematics
1 answer:
34kurt3 years ago
6 0

n, n + 2, n + 4 - three consecutive odd integers

the first is 33 less than twice the second

n - 33 = 2(n + 2)       <em>use distributive property</em>

n - 33 = (2)(n) + (2)(2)

n - 33 = 2n + 4       <em>add 33 to both sides</em>

n = 2n + 37       <em>subtract 2n from both sides</em>

-n = 37      <em>change the signs</em>

n = 37

n + 2 = 37 + 2 = 39

n + 4 = 37 + 4 = 41

<h3>Answer: 37, 39, 41</h3>
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