n, n + 2, n + 4 - three consecutive odd integers
the first is 33 less than twice the second
n - 33 = 2(n + 2) <em>use distributive property</em>
n - 33 = (2)(n) + (2)(2)
n - 33 = 2n + 4 <em>add 33 to both sides</em>
n = 2n + 37 <em>subtract 2n from both sides</em>
-n = 37 <em>change the signs</em>
n = 37
n + 2 = 37 + 2 = 39
n + 4 = 37 + 4 = 41
<h3>Answer: 37, 39, 41</h3>