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Anettt [7]
4 years ago
7

write a polar equation of a conic with the focus at the origin and the given data.hyperbola, eccentricity 3.5, directrix y

Mathematics
1 answer:
Colt1911 [192]4 years ago
7 0

Complete Question is;

Write a polar equation of a conic with the focus at the origin and the given data. hyperbola, eccentricity 3.5, directrix y =2

Answer:

r = 14/(2 + 7(sinθ))

Step-by-step explanation:

We are given;

Eccentricity;e = 3.5

Directrix; y = 2

This means that d = 2

We are told that the focus is at the origin, so since the directrix is at y = 2,then the part of the hyperbola that is closest to this focus will open downwards and the equation is given by;

r = ed/(1 + e•sinθ)

Plugging in the relevant values, we have;

r = (3.5 × 2)/(1 + 3.5(sinθ))

r = 7/(1 + 3.5(sinθ))

To make every figure a whole number, let's multiply numerator and denominator by 2 to give;

r = 14/(2 + 7(sinθ))

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3 years ago
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
ira [324]

Answer:

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Step-by-step explanation:

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depending on what its asking usually this is what its asking for but im not sure exaclty what its asking so here.....

next step is to plug the numbers in

so for the first box it says that x is -2

plug it in.....

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then keep doing it for the next boxes.....

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y = 10(-1) + 4

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y = -6

third box:

y = 10(0) + 4

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