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sergeinik [125]
3 years ago
12

What is the image of the point (6,7) after a rotation of 90 degrees counterclockwise about the origin

Mathematics
1 answer:
german3 years ago
5 0

Answer: Note the location of Point C’, the image of Point C after a 90-degree rotation. And this process could be repeated if you wanted to rotation Point C 180 degrees or 270 degrees counterclockwise: Point C after a 180-degree rotatio.

Hope it helps

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Help pls thank you!!!!
Semmy [17]

Answer:

y = 16

Step-by-step explanation:

You would plug in the value given for x into the function given.

\frac{1}{3}(18) + 10

Type that into a calculator and this would give you the output, which would be the value for Y.

The value for Y is 16.

Hope this helps.

8 0
2 years ago
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here is my question: Find the rule which gives the number of matchsticks required to make the following matchstick patterns?
kipiarov [429]
Number of matchsticks required is 2. Rule which matchstick pattern is 2 x n.
5 0
2 years ago
5 + 7 x 4 – (11 + 6)
satela [25.4K]

Answer:16

Step-by-step explanation:

Start with whats inside (11+6) (17) then you will multiply 7 and 4 = 28+5 =33 then back to 17,,,, 33-17=16

3 0
2 years ago
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I will mark you brainlist and give 5 stars! Please help!
mrs_skeptik [129]

Answer:

9A-F

9B-EI

9C-FG

Step-by-step explanation:

6 0
2 years ago
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Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
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