Answer:
Hi there!
Step-by-step explanation:
Is there anyway you can do a better picture of it please
The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
(x - x^2)^2 * sqrt(3)/4.
Integrating from x = 0 to x = 1, we have
[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4
= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.
Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
Answer:
Step-by-step explanation:
1)a) Abscissa of O 0
Abscissa of A 4
Abscissa of B -3 {opposite of 3}
Abscissa of C 3 {3 is the only positive integer like A}
Abscissa of D -4.5
Abscissa of E -6
Abscissa of F -1 {Midpoint of AE = (6+4)/2 = 10/2 = 5th number from -6 or 4}
b) OB = 3 units
DA = 8.5 {4.5 +4 = 8.5}
Answer:
=> the greatest integer is 2
the smallest integer is -2
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Step-by-step explanation:
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