Answer:
A = (16π -32) in²
P = (4π +8√2) in
Step-by-step explanation:
The area is that of a quarter-circle of radius 8 inches less half the area of a square with side length 8 inches. Two formulas are useful:
area of a circle = πr² . . . . .r = radius
area of a square = s² . . . . s = side length
Then your area is ...
A = (1/4)π(8 in)² - (1/2)(8 in)² = (64 in²)(π/4 -1/2)
A = (16π -32) in²
____
The applicable formulas for the side lengths of your figure are ...
arc BD = (1/4)(2πr) = π(r/2) = π(8 in)/2 = 4π in
segment BD = (8 in)√2
The perimeter is the sum of these lengths, so is ...
P = (4π +8√2) in
_____
Of course, you are very familiar with the fact that an isosceles right triangle with side lengths 1 has a hypotenuse of length √(1²+1²) = √2. Scaling the triangle by a factor of 8 inches means the segment AB will be 8√2 inches long.
Answer:
What time period?
Step-by-step explanation:
Answer:
1. x= -66
2, x=7
3. m= -28
4. t= -2.04 (I rounded)
5. x-(-2)=21
6. x(-2.5-3)=60
7. x≥40
Step-by-step explanation:
Answer:
Step-by-step explanation:
P = 3,000
r = 5% = 0.05
t = 9 years
Amount after 9 years is
A = P (1+ r)^t
A = 3,000(1+ 0.05)^9 = 3,000 * 1.05^9 = 4653.984648 ≈ $4,653.98
The balance after 9 years, rounded to the nearest cent is
$4,653 and 98 cents
Find the Greatest Common Factor (GCF)
GCF = 5ab
Factor out the GCF (Write the GCF first. Then, in parentheses, divide each term by the GCF.)
5ab(15a^b/5ab + -10ab^2/5ab)
Simplify each term in parentheses
<u>5ab(3a - 2b)</u>
