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olganol [36]
3 years ago
6

I need help with the first

Mathematics
1 answer:
Vladimir79 [104]3 years ago
8 0

Answer:

Step-by-step explanation:

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Write a quadratic function in vertex form whose graph has the vertex
ELEN [110]

Answer:

y = \frac{1}{2}(x - 5)² - 2

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (5, - 2), thus

y = a(x - 5)² - 2

To find a substitute (7, 0) into the equation

0 = a(7 - 5)² - 2

0 = 4a - 2 ( add 2 to both sides )

2 = 4a ( divide both sides by 4 )

a = \frac{2}{4} = \frac{1}{2}

y = \frac{1}{2} (x - 5)² - 2 ← in vertex form

4 0
3 years ago
Solve 64-31-3.64 + 22 = 38
professor190 [17]

Answer:

51.36=38

Step-by-step explanation:

You apply all these together:

64-31-3.64 + 22=51.36

51.36=38

4 0
3 years ago
What are the coordinets?
liraira [26]

Answer:

numbers that are plotted on a graph

Step-by-step explanation:

examples:

(2,8) this is a coordinate

(4,16)

(5,25)

3 0
3 years ago
Please help me<br> 2/3÷(−5/6)
agasfer [191]
I hope this helps you



2/3÷(-5/6)


2/3× -6/5


2×-6/3×5


-12/15


-4/5
3 0
3 years ago
Read 2 more answers
A right triangle has side lengths d, e, and f as shown below.
DIA [1.3K]

Answer:

and f as shown below.

Use these lengths to find cosx, sinx, and tanx.

Step-by-step explanation:

5 0
3 years ago
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