Question

How much horsepower would the Challenger Hellcat Redeye Widebody need to run the speed of sound arrive before the sound of its legendary engine arrives?
Assume Stock Redeye Widebody curb weight

Assume no wind

Assume no driveline losses

Redeye travelling at the speed of sound (760 MPH --> 1116.4ft/sec)





HP = Fsum x V/hp

F drag = 1/2 pv^2 CdA

F rolling resistance = Crr x Weight

F sum = F drag + F rolling resistance

Cd = .398

A = 26.72 Ft^2

Crr = .015

p= .002377 slugs/ft^3​

Answer 1

Answer:

The answer is based on a curb weight around 4000, you would get

37,834.2 HP

Answer 2

The Challenger Hellcat Redeye Widebody need to run the speed of sound arrive before the sound of its legendary engine arrives at 163.835 HP

Explanation:

How much horsepower would the Challenger Hellcat Redeye Widebody need to run the speed of sound arrive before the sound of its legendary engine arrives?

Horsepower is the common unit of power; i.e., the rate at which work is done. Horsepower is defined as the power that a horse gives when pulling. Horsepower is the force needed to move 550 pounds one foot in a second, or 33,000 pounds one foot in a minute.

Assume Stock Redeye Widebody curb weight

Assume no wind

Assume no driveline losses

Redeye travelling at the speed of sound (760 MPH --> 1116.4ft/sec)

$HP = Fsum * \frac{V}{hp} \\F drag =pv^2 Cd A \frac{1}{2} \\F rolling resistance = Crr x Weight\\F sum = F drag + F rolling resistance\\Cd = 0.398\\A = 26.72 Ft^2\\ Crr = 0.015 \\ p= .002377 slugs/ft^3\\​$

$P = Fsum * V\\P = F drag + F rolling resistance* V\\P = pv^2 \frac{1}{2} Cd*A + Crr* Weight* 1116.4\\\\P = 0.002377*1116.4^2 \frac{1}{2} 0.398* 26.72 + 0.015* 4451 * 1116.4\\\\\\\\P = 90289.265\\HP = \frac{P}{550} \\\\HP = \frac{90289.265}{550} \\HP = 163.835$

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