Answer:
y = (7/3)x - 9
Step-by-step explanation:
1. Convert given equation to y=mx+b form --> y = (7/3)x - 5/3
2. Equation of new line --> y = (7/3)x + b
- Note: 7/3 is the slope and for lines to be parallel they need the same slope so both equations have 7/3.
3. Plug in given values --> 5 = (7/3)(6) + b
4. Solve for b --> b = 5 - 14 b = -9
5. New line --> y = (7/3)x - 9
Answer:1
Step-by-step explanation:
37 to the nearest tenth is 40.
Solve for z:
5 (z + 6) - 2 = 9 z
5 (z + 6) = 5 z + 30:
5 z + 30 - 2 = 9 z
Add like terms. 30 - 2 = 28:
5 z + 28 = 9 z
Subtract 9 z from both sides:
(5 z - 9 z) + 28 = 9 z - 9 z
5 z - 9 z = -4 z:
-4 z + 28 = 9 z - 9 z
9 z - 9 z = 0:
28 - 4 z = 0
Subtract 28 from both sides:
(28 - 28) - 4 z = -28
28 - 28 = 0:
-4 z = -28
Divide both sides of -4 z = -28 by -4:
(-4 z)/(-4) = (-28)/(-4)
(-4)/(-4) = 1:
z = (-28)/(-4)
The gcd of 28 and -4 is 4, so (-28)/(-4) = (-(4×7))/(4 (-1)) = 4/4×(-7)/(-1) = (-7)/(-1):
z = (-7)/(-1)
(-7)/(-1) = (-1)/(-1)×7 = 7:
Answer: z = 7
y = mx + b
m = slope and b = y-intercept
We can arrange 6y = x - 12 in the form of y = mx + b
6y = x - 12
y = 1/6(x) - 2
Slope of y = 1/6(x) - 2 is 1/6. Taking the negative reciprocal of the slope we get the slope for the perpendicular line.
Negative reciprocal of 1/6 is -6.
The equation for the perpendicular line is
y = -6x + b
To find b we can plug in the x and y values of (4,-4) into it since it passes through those coordinates
-4 = -6(4) + b
b = -4 + 6(4)
b = -4 + 24
b = 20
So the equation for the perpendicular line is y = -6x + 20
