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2 years ago

John wrote so people would believe that Jesus is the Christ.

Advanced Placement (AP)

2 answers:

Margaret [11]2 years ago

7 0

1 is true

2 is true

and 3 is true

slega [8]2 years ago

4 0

1. I believe the correct answer is True.

John wrote “The Gospel of John” so people would believe that Jesus of Nazareth is the Christ, meaning that he is the Messiah prophesied in the “Old Testament”. John wanted to provide vivid portrait of Jesus to convince people that he is truly the son of God and the promised Messiah.

2. I believe the correct answer is True.

One of the purposes for writing “The Gospel of John” is John’s wish for people to find eternal life in the Son of God: “But these are written so that you may believe that Jesus is the Christ, the Son of God, and that by believing you may have life in His name.” (John 20:30-31)

3. I believe the correct answer is the Son of God.

In the “Gospel of John”, Apostle John wants people to believe that to Jesus is the Son of God and that in Him we see the unseen God: “And the Word became flesh, and dwelt among us, and we saw His glory, glory as of the only begotten from the Father, full of grace and truth.”(John 1:14)

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3 years ago

Airborne chemical substances travel up the nose to the olfactory_____, which is the receptor got smell

Vlada [557]

Answer:

c) bulb

Explanation:

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3 years ago

There was unrest in the areas under Napoleon's control because he:

Ierofanga [76]

Answer:

it is a letter C

Explanation:

I hope this my answer can help you

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3 years ago

I can’t figure this problem out

Natalka [10]

Answer:

Explanation:

Alright so the way to do this is to use properties of integrals to make our life easier.

So we have:

$\int\limits^4_1 {(3f(x)+2)} \, dx$

So lets break this up into two different integrals that represent the same area.

$\int\limits^4_0 {f(x)} \, dx - \int\limits^1_0 {f(x)} \, dx = \int\limits^4_1 {f(x)} \, dx$

Lets think about what is going on up there. The integral from four to zero gives us the area under the curve of f(x) from four to zero. If we subtract this from the integral from one to zero (the area under f from one to zero) we are left with the area under f from four to one! Hence:

$\int\limits^4_1 {f(x)} \, dx$

But since we have these values we can say that:

-3 - 2 = -5

Which means that $\int\limits^4_1 {f(x)} \, dx$ = -5

So now we can evaluate $\int\limits^4_1 {(3f(x)+2)} \, dx$

Lets first break up our integrand into two integrals

$\int\limits^4_1 {(3f(x)+2)} \, dx$ = $3\int\limits^4_1{f(x)} \, dx + 2\int\limits^4_1 {} \, dx$

Now we can evaluate this:

We know that $\int\limits^4_1 {f(x)} \, dx$ = -5

So:

$3(-5)+2[x]$ where x is evaluated at 4 to 1 so

-15 + 2(3)

So we are left with -15 + 6 = -9

5 0

3 years ago

Imagine someone who is depressed, and goes to a positive psychologist for therapy. Write about what positive psychologists do, a

expeople1 [14]

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3 years ago