Ask question

Ask question

All categories

3 years ago

10

The MAD for the fall data is 2.8 cookies. The MAD for the spring data is 2.6 cookies. Express the difference in means as a multi

ple of the larger MAD.
(The mean for the spring is 24 and the mean for the fall is 23.)

1 answer:

Ket [755]3 years ago

3 0

Answer:

1.2

sorry if its not the right problem

Step-by-step explanation:

You might be interested in

The vertex angle of an isosceles triangle measures 40°. What is the measure of a base angle?

skad [1K]

In all triangles, inner angles add to 180 degrees.
In an isosceles triangle, the base angles are the same and the vertex angle is different from the rest.

b= (180-40)/2
b= 140/2
b=70

Final answer: 70 degrees

8 0

3 years ago

Kayaks rent for $35 per day. Which expression can you use to find the cost in dollars of renting 3 kayaks for a day?

Murrr4er [49]

Answer:

$105

Step-by-step explanation:

assuming that it costs $35 dollars for renting 1 kayak per day:

3 * 35 = k 3 is for the # of kayaks and 35 is the cost

105 = k multiply 35 w/ 3 to get the answer

6 0

4 years ago

Between x = 2 and x = 3, which function has a greater average rate of change than y = 1 3 -x ?

Fudgin [204]

Y = 1 3 -x = left[y \right] = \left[ 3-x\right][y]=[3−x]

7 0

3 years ago

I NEED HELP PLZ!!!!!! 20 POINTS

Amanda [17]

Answer:

1 is c

2 is d

3 is a

Step-by-step explanation:

Sorry it took a bit not pretty good at these but i used an app called desmos and it basically gives the answer

5 0

3 years ago

Given points A (1, 2/3), B (x, -4/5), and C (-1/2, 4) determine the value of x such that all three points are collinear

AlladinOne [14]

Answer:

$x=\frac{83}{50}$

Step-by-step explanation:

we know that

If the three points are collinear

then

$m_A_B=m_A_C$

we have

A (1, 2/3), B (x, -4/5), and C (-1/2, 4)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

step 1

Find the slope AB

we have

$A(1,\frac{2}{3}),B(x,-\frac{4}{5})$

substitute in the formula

$m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}$

$m_A_B=\frac{\frac{-12-10}{15}}{x-1}$

$m_A_B=-\frac{22}{15(x-1)}$

step 2

Find the slope AC

we have

$A(1,\frac{2}{3}),C(-\frac{1}{2},4)$

substitute in the formula

$m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}$

$m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}$

$m_A_C=-\frac{20}{9}$

step 3

Equate the slopes

$m_A_B=m_A_C$

$-\frac{22}{15(x-1)}=-\frac{20}{9}$

solve for x

$15(x-1)20=22(9)$

$300x-300=198$

$300x=198+300$

$300x=498$

$x=\frac{498}{300}$

simplify

$x=\frac{83}{50}$

8 0

4 years ago