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3 years ago

What would these be :)

Mathematics

1 answer:

Minchanka [31]3 years ago

8 0

Y= -5
f= 7
d= 1.9
it’s the answer

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Lee has a jar of 100 pennies. She adds groups of 10 pennies to the jar. She adds 5 groups. What numbers does she say?

Alenkinab [10]

150 pennies in the jar .

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2 years ago

Mr. Arnold drives 130 miles round trip to work 5 days a week. Write and solve an equation to find how many miles he drives in 60

mart [117]

Answer:

The answer is D.

Step-by-step explanation:

130 x 60 = 7,800 miles. you don't need the extra information "5 days a week" to solve the problem.

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3 years ago

What’s is the solution to the equation x to the power of 2 =16/25

skelet666 [1.2K]

Answer:

$x=\dfrac{4}{5}$

Step-by-step explanation:

The given equation is :

$x^2=\dfrac{16}{25}$

We need to find the value of x.

When the exponent 2 removes from LHS, it will shift to RHS as square root as follows :

$x=\sqrt{\dfrac{16}{25}}$

We know that, 4×4= 16 and 5×5 = 25

So,

$x=\sqrt{\dfrac{4\times 4}{5\times 5}}\\\\x=\dfrac{4}{5}$

So, the solution of the given equation is 4/5.

4 0

2 years ago

A sample of gold has a mass of 579 g. The volume of the sample is 30 cm3. What is the density of the gold sample?

Ugo [173]

The density of the gold sample is 19.3g/cm³

Let the mass of the gold sample be represented by m

m = 579 g

Let the volume of the gold sample be represented by V

V = 30 cm³

Let the density of the gold sample be represented by ρ

The formula for the density is:

$Density = \frac{Mass}{Volume}$

$\rho = \frac{m}{V} \\\rho = \frac{579}{30} \\\rho = 19.3 g/cm^3$

The density of the gold sample is 19.3g/cm³

Learn more here: brainly.com/question/17780219

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2 years ago

Caroline answered 47 out of 56 questions correctly on her test. What percent of the questions did Caroline get correct

Aleksandr [31]

Answer:

Step-by-step explanation:

<h3>Convert fraction (ratio) 47 / 56 Answer: 83.928571428571%</h3>

6 0

3 years ago

Read 2 more answers