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LiRa [457]
3 years ago
9

What is the approximate length of the radius of a circle with a circumference of 63 inches?

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
5 0

Answer: 63/2π

Step-by-step explanation: C=πd  

                                             63=πd

                                             D=63/π

r=1/2d

1/2×63/π=<u>63/2π</u>

       

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netineya [11]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Find the modulus of the complex number 6-2i
Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

Step-by-step explanation:

Given the number

6-2i

We know that

z = x + iy

where x and y are real and \sqrt{-1}=i

The modulus or absolute value of z is:

|z|\:=\sqrt{x^2+y^2}

Therefore, the modulus of 6-2i  will be:

z=6-2i

z=6+(-2)i

|z|\:=\sqrt{x^2+y^2}

|z|\:=\sqrt{6^2+\left(-2\right)^2}

    =\sqrt{6^2+2^2}

    =\sqrt{36+4}

    =\sqrt{40}

    =\sqrt{2^2}\sqrt{2\cdot \:5}

    =2\sqrt{2\cdot \:5}

   =2\sqrt{10}

Therefore, the modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

3 0
2 years ago
How do you write -44.09 as a fraction?
julsineya [31]

Answer:

-4409/100

bcoz there is decimal next to 2 numbers

4 0
3 years ago
Read 2 more answers
Can someone tell me what is 8/9+3/5
I am Lyosha [343]
Okay I am going to explain to you and show you how to get the correct answer.

Fist you need to find the Greatest common factor which is 45 because 5×9=45

8/9=40/45

+3/5=27/45
__________
67/45 is reduced to 1 22/45
5 goes into 45 9 times so 3 times 7 equals 27 and 9 goes into 45 5 times so 8 times 5 equals 40 you add both numbers up and get 67. 67 can't go into 45 so you subtract 67 from 45. 45 goes into 67 1 time so that is your whole the number. 22 is left over so that is your numerator. The denominator remains the same.
5 0
3 years ago
(-2,3) is one vertex of a square on a coordinate plane. Name three points that could be the other vertices.
wariber [46]
Well basically you just have to chose a number of sides for the side length of the square to be and move those many places to get another vertex of the square. For example if we have (-2,3) and we choose the side lengths to be 4 units than you could move 4 places up, down, left, or right to get the other vertices for the square


Hope that helps :)
3 0
2 years ago
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