Border of the pool means "perimeter".
P = 2L + 2W (L represents length, W represents width)
P = 2(3s) + 2(2s)
P = 6s + 4s
P = 10s
X=6 2+1=3 and 3 x 2=6 so x is 6
Answer:
u = -2, -3/5
General Formulas and Concepts:
<u>Algebra I</u>
- Standard Form: ax² + bx + c = 0
- Factoring
- Finding roots
Step-by-step explanation:
<u>Step 1: Define equation</u>
5u² + 6 = -13u
<u>Step 2: Solve for </u><em><u>u</u></em>
- Rewrite: 5u² + 13u + 6 = 0
- Factor: (u + 2)(5u + 3) = 0
- Find roots: u = -2, -3/5
Answer:
ABC shaded area = 36
- 72 cm²
ABC shaded area perimeter =
cm
ABCD area =
cm²
ABCD perimeter =
cm
Step-by-step explanation:
<u>Shape ABC</u>
Assuming you want the area and perimeter of the shaded part of the shape only...
<u>Area</u>
Area of a sector =
(where r is the radius and
<em> </em>
⇒ area of a sector = 
Area of triangle = 1/2 x base x height
⇒ area of triangle = 1/2 x 12 x 12 = 72 cm²
Therefore, area of shaded area = area of sector - area of triangle
⇒ area = 36
- 72 cm²
<u>Perimeter</u>
Arc length =
(where r is the radius and
<em> </em>
⇒ arc length = 
Hypotenuse of triangle =
(where a and b are the legs of the right triangle)
⇒ hypotenuse =
cm
Therefore, perimeter = arc length + hypotenuse
⇒ perimeter =
cm
<u>Shape ABCD</u>
<u>Area</u>
Area of a semicircle =
(where r is the radius)
⇒ area of large semicircle ABC = 
⇒ area of small semicircle AD = 
⇒ area of shape ABCD = 
<u>Perimeter</u>
1/2 circumference = 
⇒ perimeter = 