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3241004551 [841]
3 years ago
6

What is the point-slope form of a line with slope -4 that contains the point (-2, 3?

Mathematics
2 answers:
olga_2 [115]3 years ago
6 0
The point-slope equation of a line that cointains the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)

so
point (-2,3) and slope -4
y-3=-4(x-(-2))
y-3=-4(x+2) is da equation
goblinko [34]3 years ago
3 0

Answer:

y-3=-4(x+2)

Step-by-step explanation:

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What is the equation of the line that passes through (5, 3) and (4, 5)
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Answer:

y = - 2x + 13

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (5, 3) and (x₂, y₂ ) = (4, 5)

m = \frac{5-3}{4-5} = \frac{2}{-1} = - 2, thus

y = - 2x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (4, 5), then

5 = - 8 + c ⇒ c = 5 + 8 = 13

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Answer:

The answer to your question is: the last option

Step-by-step explanation:

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