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timofeeve [1]
3 years ago
6

How many solutions does the following system of equations have? 2y= 5x + 4 1 = 3x + 2

Mathematics
1 answer:
Elden [556K]3 years ago
4 0

Looks like a pretty regular system, no parallel lines.  In fact the second equation is a vertical line as written; not sure if that's a typo.  Either way,

Answer: EXACTLY ONE SOLUTION

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`find the equatifindon of tangent and normal of parabola y²=16ax at point whose coordinate is -5a. ​
marusya05 [52]

Answer:

\rm \displaystyle y _{ \rm tangent} =   - \frac{8}{5} x -  \frac{5}{2} a

\rm \displaystyle y _{ \rm normal} =  \frac{5}{8} x  -  \frac{765}{128} a

Step-by-step explanation:

we are given a equation of parabola and we want to find the equation of tangent and normal lines of the Parabola

<u>finding</u><u> the</u><u> </u><u>tangent</u><u> </u><u>line</u>

equation of a line given by:

\displaystyle y = mx + b

where:

  • m is the slope
  • b is the y-intercept

to find m take derivative In both sides of the equation of parabola

\displaystyle   \frac{d}{dx} {y}^{2} =  \frac{d}{dx} 16ax

\displaystyle   2y\frac{dy}{dx}=  16a

divide both sides by 2y:

\displaystyle   \frac{dy}{dx}=   \frac{16a}{2y}

substitute the given value of y:

\displaystyle   \frac{dy}{dx}=   \frac{16a}{2( - 5a)}

simplify:

\displaystyle   \frac{dy}{dx}=    - \frac{8}{5}

therefore

\displaystyle    m_{ \rm tangent} =    - \frac{8}{5}

now we need to figure out the x coordinate to do so we can use the Parabola equation

\displaystyle ( - 5a {)}^{2}  = 16ax

simplify:

\displaystyle x =  \frac{25}{16} a

we'll use point-slope form of linear equation to get the equation and to get so substitute what we got

\rm \displaystyle y - (  - 5a)=   - \frac{8}{5} (x -  \frac{25}{16} a)

simplify which yields:

\rm \displaystyle y =   - \frac{8}{5} x - \frac{5}{2} a

<u>finding</u><u> the</u><u> </u><u>equation</u><u> </u><u>of </u><u>the</u><u> </u><u>normal</u><u> </u><u>line</u>

normal line has negative reciprocal slope of tangent line therefore

\displaystyle    m_{ \rm normal} =     \frac{5}{8}

once again we'll use point-slope form of linear equation to get the equation and to get so substitute what we got

\rm \displaystyle y - (  - 5a)=   \frac{5}{8} (x -  \frac{25}{16} a)

simplify which yields:

\rm \displaystyle y =  \frac{5}{8} x  -  \frac{765}{128} a

and we're done!

( please note that "a" can't be specified and for any value of "a" the equations fulfill the conditions)

8 0
3 years ago
Read 2 more answers
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konstantin123 [22]

Answer:

Hello

Here's the answer:

2x^2 + 5x + 2 = 0\\&#10;2x^2+4x+x+2=0\\&#10;2x(x+2)+1(x+2)=0\\&#10;(2x+1)(x+2)=0\\&#10;x=-\frac{1}{2} \vee x=-2

x^2-4x+1=0\\&#10;x^2-4x+4-3=0\\&#10;(x-2)^2=3\\&#10;x-2 =\sqrt3 \vee x-2=-\sqrt3\\&#10;x=2+\sqrt3 \vee x=2-\sqrt3

Step-by-step explanation:

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Sergeu [11.5K]

Answer:

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Step-by-step explanation:

Set this problem up with a porportion.

\frac{?}{260} \frac{25}{100}

After that, cross multiple and divide.

25 times 260. Then divide by 100. That is then your answer.

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If the length of FH is 18 units, what is the value of x?
valentinak56 [21]
Well if FG is 4x and GH is 2x the you add them to get 6x for FH. Solve for x so 6x=18 which means x=3. Hope this helps
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erma4kov [3.2K]

Answer:

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Step-by-step explanation:

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