I don’t know how to do this question

Mikayla is buying deli meat and cheese for sandwiches for a family reunion. How much will she spend on 4.5 pounds of ham and 3.5

yanalaym [24]

4.5(4.59) + 3.5(3.79) = 20.66 + 13.27 = 33.93 <==

8 0

3 years ago

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The length of a rectangle is 11 in. longer than its width. The perimeter of the rectangle is 86 in.

katen-ka-za [31]

$L=w+11 \\\\P=86in \\P=2L+2w \\\\ 2(w+11)+2w=86 \\\\ 2w+22+2w=86 \\\\ 4w=86-22 \\\\ 4w=64 \\\\ \boxed{w=\frac{64}{4}=16in} \\\\L=16+11 \\\\ \boxed{L=27in}$

6 0

4 years ago

A paper reported that in a representative sample of 282 American teens age 16 to 17, there were 71 who indicated that they had s

elena-s [515]

Answer:

$z=\frac{0.252 -0.25}{\sqrt{\frac{0.25(1-0.25)}{282}}}=0.0776$

$p_v =P(z>0.0776)=0.4691$

Since the p value is higher than the significance level so then we can conclude that we have enough evidence to FAIL to reject the null hypothesis and there is no evidence in order to say that the true proportion of teens more than a quarter of Americans age 16 to 17 have sent a text message while driving is higher than 0.25

Step-by-step explanation:

Information provided

n=282 represent the sample selected

X=71 represent the teens indicated that they had sent a text message while driving

$\hat p=\frac{71}{282}=0.252$ estimated proportion of teens indicated that they had sent a text message while driving

$p_o=0.25$ is the value that we want to test

$\alpha=0.01$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to check if more than a quarter of Americans age 16 to 17 have sent a text message while driving, and the hypothesis are:

Null hypothesis: $p\leq 0.7$

Alternative hypothesis: $p > 0.25$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing we got:

$z=\frac{0.252 -0.25}{\sqrt{\frac{0.25(1-0.25)}{282}}}=0.0776$

Decision

The p value for this case is:

$p_v =P(z>0.0776)=0.4691$

Since the p value is higher than the significance level so then we can conclude that we have enough evidence to FAIL to reject the null hypothesis and there is no evidence in order to say that the true proportion of teens more than a quarter of Americans age 16 to 17 have sent a text message while driving is higher than 0.25

8 0

4 years ago

A rectangle that is 6 feet by 9 feet has been scaled by a factor of 1/3.

OleMash [197]

The side lengths of the scaled copy are 2 feet by 3 feet and to scale the copy back to its original size, the scale factor to use is 3

<h3>1. What are the side lengths of the scaled copy? feet by feet</h3>

The given parameters are:

Length = 6 feet

Width = 9 feet

The scale factor is given as:

k = 1/3

So, the side lengths of the scaled copy are

Length = 1/3 * 6 feet = 2 feet

Width = 1/3 * 9 feet = 3 feet

Hence, the side lengths of the scaled copy are 2 feet by 3 feet

<h3>2. Suppose you want to scale the copy back to its original size. What scale factor should you use?</h3>

In (1), we have:

The scale factor is given as:

k = 1/3

To scale the copy back to its original size, the scale factor to use is:

Scale = 1/(1/3)

Evaluate

Scale = 3

Hence, to scale the copy back to its original size, the scale factor to use is 3