Question

A line passes through the point (2, 10) and has a y-intercept of 4. What is the equation of the line?

Answer 1

Answer:

$y=3x+4$

Step-by-step explanation:

Hi there!

What we need to know:

• Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x is equal to 0)

1) Determine the slope (m)

$m=\frac{y_2-y_1}{x_2-x_1}$ where two points that the line passes through are $(x_1,y_1)$ and $(x_2,y_2)$

We're given the point (2,10) and the y-intercept of 4. Recall that the y-intercept occurs when x is equal to 0. This means that the y-intercept occurs at (0,4), giving us our second point.

Plug these points into the equation

$=\frac{10-4}{2-0}\\=\frac{6}{2}\\=3$

Therefore, the slope of the line is 3. Plug this into $y=mx+b$

$y=3x+b$

2) Determine the y-intercept (b)

The y-intercept is given; it is 4. Plug this back into $y=3x+b$

$y=3x+4$

I hope this helps!