The chemical formula of <span>aluminum phosphate is
AlPO</span>₄
Using this formula E = mc2, which is the formula formulated by Albert Einstein to get the energy where E is the units of energy, m is the mass and c is the speed of light. We can say that 1 g is equivalent to 0.001 kg. The speed of light is 38<span>. Substituting these values to the formula, we can get 90 terajoules.</span>
160 g of SO3 are needed to make 400 g of 49% H2SO4.
<h3>How many grams of SO3 are required to prepare 400 g of 49% H2SO4?</h3>
The equation of the reaction for the formation of H2SO4 from SO3 is given below as follows:
1 mole of SO3 produces 1 mole of H2SO4
Molar mass of SO3 = 80 g/mol
Molar mass of H2SO4 = 98 g/mol
80 g of SO3 are required to produce 98 og 100%H2SO4
mass of SO3 required to produce 400 g of 100 %H2SO4 = 80/98 × 400 = 326.5 g of SO3
Mass of SO3 required to produce 49% of 400 g H2SO4 = 326.5 × 49% = 160 g
Therefore, 160 g of SO3 are needed to make 400 g of 49% H2SO4.
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Answer: Glucose is an example of carbon-based macromolecule known as carbohydrates
Explanation:
carbon based macromolecule are important cellular components and they perform a variety of functions necessary for growth and development of living organisms. There are 4 major types of carbon based molecules and these includes;
Carbohydrate
Lipids
Proteins and
Nucleic acids.
Carbon is the primary components of these macromolecules. Carbohydrate macromolecules are made up of monosaccharide, disaccharide and polysaccharides. Glucose is an example of a monosaccharide and it has two important types of functional groups: a carbonyl group and a hydroxyl group. I hope this helps. Thanks
Answer: The specific heat of the liquid is 
Explanation:
As we know that,
.................(1)
where,
q = heat absorbed or released
= mass of glass = x kg
= mass of liquid = x kg
= final temperature =
= temperature of glass = 
= temperature of liquid = 
= specific heat of glass = 
= specific heat of liquid= ?
Now put all the given values in equation (1), we get
![-[(x\times 840\times (53-83)]=x\times c_2\times (53-43)](https://tex.z-dn.net/?f=-%5B%28x%5Ctimes%20840%5Ctimes%20%2853-83%29%5D%3Dx%5Ctimes%20c_2%5Ctimes%20%2853-43%29)
Therefore, the specific heat of the liquid is
