If a piece of charcoal is taken and set on fire it will evolve CO2 and heat. Charcoal is solid but carbon dioxide is gaseous. This is an example of change of state and evolve of heat during chemical reaction.
Cause it felt like being cold
Answer:
Constraints are restrictions that need to be placed upon variables
Explanation:
Constraints are restrictions (limitations, boundaries) that need to be placed upon variables used in equations that model real-world situations. It is possible that certain solutions which make an equation true mathematically, may not make any sense in the context of a real-world word problem.
Answer:
Explanation:
The missing image is attached below.
The objective of this question is to draw the major product formed from the diagram attached below.
From the diagram attached, we will see the reaction of a tertiary alkyl halide together with a weak nucleophile (ch3ch2oh) undergoing a nucleophilic substitution (SN₁) mechanism to yield a racemic mixture(i.e., compound that is not optically active but contains an equal amount of dextrorotatory and levorotatory stereoisomers) as a product.
Answer:
The correct answers are: <u>Each oxygen of carbonate ion has -2/3 or -0.67 charge.</u>
<u>Bond order of each carbon‑oxygen bond in the carbonate ion</u> = <u>1.33</u>
Explanation:
The carbonate ion (CO₃²⁻) is an organic compound, in which a carbon atom is covalently bonded to three oxygen atoms. The net formal charge on a carbonate ion is −2.
The carbonate ion is <u>resonance stabilized</u> and has three equivalent resonating structures, which exhibits that all the three carbon-oxygen bonds in a carbonate ion are equivalent.
In the resonance hybrid of carbonate ion,<u> the negative charge is equally delocalized on all the three oxygen atoms. </u>
<u>Thus, each bonded oxygen has -2/3 or -0.67 charge.</u>
<u />
In a carbonate ion there is one double bond oxygen (C=O) and two single bonded oxygen (C-O). Bond order of 1 C=O is 2 and bond order of C-O is 1.
∴ <u>Bond order</u> = sum of all bond orders ÷ number of bonding groups = (2+1+1) ÷ 3 = <u>1.33</u>
