Autoionization Reactions are those reactions in which ions or molecules ionizes spontaneously without adding any external reagent.
For Example,
Autoionization of water.
H₂O + H₂O ⇆ H₃O⁺ + OH⁻
Autoionization reaction of Methanol is shown below,
The answer to this question is 159.609 g/mol
Hello!
If the reaction could be made to go faster B. The hill would be shorter.
The "hill" is called Activation Energy. It is the energy of the activated intermediate compound needed to complete the reaction. Catalysts are substances that don't intervene in the reaction which speed up the rate of a given reaction by lowering the Activation Energy giving alternate reaction pathways with lower-energy intermediates. If the reaction could be made to go faster with the use of a catalyst, then the Activation Energy would be lower and the "hill" would be shorter.
Have a nice day!
<span>69.3 g
First, determine the molar masses involved:
Atomic weight iron = 55.845
Atomic weight carbon = 12.0107
Atomic weight oxygen = 15.999
Molar mass Fe2O3 = 2 * 55.845 + 3 * 15.999 = 159.687 g/mol
Molar mass CO = 12.0107 + 15.999 = 28.0097 g/mol
Determine how many moles of each reactant we have
Moles Fe2O3 = 189 g / 159.687 g/mol = 1.18356535 mol
Moles CO = 63.0 g / 28.0097 g/mol = 2.249220806 mol
For every mole of Fe2O3, we need 3 moles of CO. So let's see how many moles of Fe2O3 is consumed by dividing moles CO by 3.
2.249220806 mol / 3 = 0.749740269 mol
So we'll be consuming 0.749740269 moles of Fe2O3, subtract that from what we started with
1.18356535 mol - 0.749740269 mol = 0.433825081 mol
Now multiply by the molar mass of Fe2O3
0.433825081 mol * 159.687 g/mol = 69.27622574 g
Rounding to 3 significant figures gives 69.3 g</span>
Answer: 0.02 molecules
The mass of sodium chloride= 23+35.5 = 58.5g
No. Of moles= Molar mass of NaCI
1.17 divided by 58.5 = 0.02
