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mario62 [17]
3 years ago
5

How does vibrational energy contribute to a reaction?

Chemistry
1 answer:
Viefleur [7K]3 years ago
6 0

Answer:

A lot of thing tbh

Explanation:

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Diffusion of nonpolar molecules would not be affected by
wariber [46]
 +molecule size +steepness of the concentration gradient +temperature + steepness of the electric gradient +steepness
7 0
3 years ago
Newton's second law of motion uses the formula which states that a force will cause a mass to accelerate. (f = m •
Makovka662 [10]

Newton's second law of motion can be formally stated as follows:

The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

This verbal statement can be expressed in equation form as follows:

a = Fnet / m

7 0
3 years ago
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5. What volume of silver metal will weigh exactly 4500.0 g. The density of silver is 20.5 g/cm.
Vitek1552 [10]

Answer:

The answer is

<h2>219.5 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question

mass = 4500 g

density = 20.5 g/cm³

We have

volume =  \frac{4500 }{20.5}  \\  = 219.51219...

We have the final answer as

<h3>219.51 mL</h3>

Hope this helps you

8 0
3 years ago
Assuming that sea water is a 3.5 wt % solution of NaCl in water, calculate its osmotic pressure at 20°C. The density of a 3.5% N
olga nikolaevna [1]

Answer:

π = 14.824 atm

Explanation:

wt % = ( w NaCL / w sea water ) * 100 = 3.5 %

assuming w sea water = 100 g = 0.1 Kg

⇒ w NaCl = 3.5 g

osmotic pressure ( π ):

  • π = C NaCl * R * T

∴ T = 20 °C  + 273 = 293 K

∴ C ≡ mol/L

∴ density sea water = 1.03 Kg/L....from literature

⇒ volume sea water = 0.1 Kg * ( L / 1.03 Kg ) = 0.097 L sln

⇒ mol NaCl = 3.5 g NaCL * ( mol NaCL / 58.44 g ) = 0.06 mol

⇒ C NaCl = 0.06 mol / 0.097 L = 0.617 M

⇒ π = 0.617 mol/L * 0.082 atm L / K mol * 293 K

⇒ π = 14.824 atm

7 0
3 years ago
Trisha and her lab partner filled a beaker with 150 milliliters of a 0.10 M HCl solution. How many moles of HCl are in the beake
oksian1 [2.3K]
M=mol/liter
We know that we have 150ml=.15 L and .1 mol of HCl
Rearranging the molarity equation, we get
mol=M*l
mol=(.15)(.1)
=.015 mol
7 0
3 years ago
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