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nexus9112 [7]
3 years ago
12

Translate the algebraic expression shown below into a verbal expression x/10?

Mathematics
1 answer:
sladkih [1.3K]3 years ago
4 0
I believe it is verbally expressed as x divided by ten.
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M²-2m=0 how do i finish this?
Degger [83]

Answer:

m = 0 or m = 2

Step-by-step explanation:

m² - 2m = 0

m ( m − 2 ) = 0

m = 0

m − 2 = 0

m = 2

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Solve the triangle A = 2 B = 9 C =8
VARVARA [1.3K]

Answer:

\begin{gathered} A=\text{ 12}\degree \\ B=\text{ 114}\degree \\ C=54\degree \end{gathered}

Step-by-step explanation:

To calculate the angles of the given triangle, we can use the law of cosines:

\begin{gathered} \cos (C)=\frac{a^2+b^2-c^2}{2ab} \\ \cos (A)=\frac{b^2+c^2-a^2}{2bc} \\ \cos (B)=\frac{c^2+a^2-b^2}{2ca} \end{gathered}

Then, given the sides a=2, b=9, and c=8.

\begin{gathered} \cos (A)=\frac{9^2+8^2-2^2}{2\cdot9\cdot8} \\ \cos (A)=\frac{141}{144} \\ A=\cos ^{-1}(\frac{141}{144}) \\ A=11.7 \\ \text{ Rounding to the nearest degree:} \\ A=12º \end{gathered}

For B:

\begin{gathered} \cos (B)=\frac{8^2+2^2-9^2}{2\cdot8\cdot2} \\ \cos (B)=\frac{13}{32} \\ B=\cos ^{-1}(\frac{13}{32}) \\ B=113.9\degree \\ \text{Rounding:} \\ B=114\degree \end{gathered}\begin{gathered} \cos (C)=\frac{2^2+9^2-8^2}{2\cdot2\cdot9} \\ \cos (C)=\frac{21}{36} \\ C=\cos ^{-1}(\frac{21}{36}) \\ C=54.3 \\ \text{Rounding:} \\ C=\text{ 54}\degree \end{gathered}

3 0
1 year ago
Evaluate:<br> g(x) = 3•2^x+2 + 3<br> g(3)
sertanlavr [38]

If the 3 is supposed to be replaced by any x's, then the answer would be 29 I believe.

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3 years ago
Cannnn iiii please get helpppp
Feliz [49]

Answer:

what is this

Step-by-step explanation:

5 0
3 years ago
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