Ask question

Ask question

All categories

2 years ago

14

The floor plan of a proposed auditorium shows a stage that measures 1.75 inches in width . The scale of the floor plan is 1 in =

18ft . What is the width of the proposed stage ?

1 answer:

Nikolay [14]2 years ago

8 0

Answer:

31.5

Step-by-step explanation:

so if they say that every inch is realy 18 ft and u have 1.75 inches then multiply 8 by 1.75 to get the width of the stage

You might be interested in

PLEASE HELP!<br><br> Reduce to simplest form.<br> 5/8 - (- 7/2)

Daniel [21]

Answer:

$\huge\boxed{\sf 4\frac{1}{8} }$

Step-by-step explanation:

$\sf =\frac{5}{8} - (-\frac{7}{2} )\\\\Rule : ( - *- = +)\\\\\=\frac{5}{8} +\frac{7}{2} \\\\LCM = 8\\\\\=\frac{5+28}{8} \\\\\=\frac{33}{8} \\\\=4\frac{1}{8}$

$\sf =\frac{5}{8}+ \frac{7}{2} \\\\=\frac{5+28}{8}$

$\sf =\frac{33}{8} \\\\=4\frac{1}{8}$

Hope this helped!

<h2>~AnonymousHelper1807</h2>

7 0

2 years ago

3x-4y+6=0 solve for y

DiKsa [7]

Answer: y=3/4x+3/2

Step-by-step explanation:

Let's solve for y.

3x−4y+6=0

Step 1: Add -3x to both sides.

3x−4y+6+−3x=0+−3x

−4y+6=−3x

Step 2: Add -6 to both sides.

−4y+6+−6=−3x+−6

−4y=−3x−6

Step 3: Divide both sides by -4.

−4y/−4= −3x−6/−4

y=3/4x+3/2

5 0

2 years ago

Brown has own bakery he baked 5 cakes per day due to occasional christmas story to be in the whole christmas week how many cakes

Lena [83]

she would make 35 cakes

8 0

2 years ago

(cotx+cscx)/(sinx+tanx)

Butoxors [25]

Answer: $\bold{\dfrac{cot(x)}{sin(x)}}$

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

$\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)$

$\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)$

$\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}$

6 0

3 years ago

ASAP plz!!!!!!!!<br> 10 points

mojhsa [17]

FHdhdhdhhdhdjdjddjjdjsjxjxjdjxjdAnswer:

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers