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Inverse variation has the form of y=k/x. So you have the form of:
<span>V = k/P, plug in values of V and P to find k: </span>
<span>200 = k/32 </span>
<span>k = 6400 </span>
<span>So, your formula is V = 6400/P </span>
<span>V = 6400/20 </span>
<span>V = 320 </span>
Answer:
See the answers and explanation below
Explanation:
To solve this problem, we must have the full description of this problem, by doing an internet search we can find a problem with the same description and with the respective question.
<u>Description of the problem</u>
<u />
"Vertically oriented circular disks have strings wrapped around them. The other ends of the strings are attached to hanging masses. The diameters of the disks, the masses of the disks, and the masses of the hanging masses are
given. The disks are fixed and are not free to rotate. Specific values of the variables are given in the figures. Rank these situations, from greatest to least, on the basis of the magnitude of the torque on the disks. That is, put first the situation where the disk has the greatest torque acting on it and put last the situation where the disk has the least torque acting on it."
<u>For case D</u>
<u />
T = (20/2)*800 = 8000 [g-cm]
<u>For case A</u>
<u />
T = (20/2)*500 = 5000 [g-cm]
<u>For case C</u>
<u />
T = (10/2)*500 = 2500 [g-cm]
<u>For case B</u>
<u />
T = (10/2)*200 = 1000 [g-cm]
In this way it has been organized from the largest to the smallest torque present in each of the cases.
Answer:
pretty sure its A
Explanation:
please give brainliest if i'm correct
Answer:
Rod will remain horizontal all the time after release.
Explanation:
This is because net torque on the rod about any point in space is zero.
Let assume that distance between the two masses m and 2m is L.
Also m is situated at origin and in positive XY direction.
Then , Center of mass is at L()
COM =
So let us calculate net torque about hinged point which COM.
- Torque because of hinge force is zero because it passes from that point itself.
- Torque on 2m mass is 2mg(L/3) in nenegative Z direction.
- Torque on m mass is mg(2L/3) in positive Z direction.
As both torque are equal and opposite then net torque =0.
Thus it got balanced.
Answer:
she will eventually slow down and come to a stop