The chemical element of atomic number 12,
Answer:
A. (1/T₂ - 1/T₁) = -2.69 x 10⁻⁴ K⁻¹
B. ln (k₁/k₂) = -3.434
C. E = 106.13 KJ/mol
Explanation:
Part A:
we have:
T₁ = 25°C = 298 K
T₂ = 51°C = 324 K
(1/T₂ - 1/T₁) = (1/324 k - 1/298 k)
<u>(1/T₂ - 1/T₁) = -2.69 x 10⁻⁴ K⁻¹</u>
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Part B:
ln (k₁/k₂) = ln (0.1/3.1)
<u>ln (k₁/k₂) = -3.434</u>
Part C:
The activation energy can be found out by using Arrhenius Equation:
ln (k₁/k₂) = E/R (1/T₂ - 1/T₁)
where,
E = Activation Energy
R = General Gas Constant = 8.314 J/mol.k
Therefore,
-3.434 = (E/8.314 J/mol.k)(-2.69 x 10⁻⁴ K⁻¹)
<u>E = 106134.8 J/mol = 106.13 KJ/mol</u>
Answer: higher temperature increases reaction rates for both endothermic and exothermic reactions
Explanation: i took the test
Answer:
a. Both wires have the same resistivity
Explanation:
For the resistance of a wire , following formula holds good .
R = ρ l / S , R is resistance , l is length , S is cross sectional area and ρ is resistivity of the material that the wire is made of. Resistance is dependent on length and cross sectional area but resistivity does not depend upon length or cross sectional area . It only depends upon the type of material.
If we replace copper wire with aluminium wire , then resistivity will change .
Hence , since the wire remains made of copper , resistivity will not change.