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postnew [5]
4 years ago
12

The 11 th one please! Somebody help me:(

Physics
1 answer:
photoshop1234 [79]4 years ago
5 0

Answer:

203360Pa

Explanation:

Pressure= density of liquid*height*g

=1000*10*10

=100000Pa

Total pressure= water pressure + atmospheric pressure

=1000000+103360

=203360 Pascal

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A resistor, an inductor, and a switch are all connected in series to an ideal battery of constant terminal voltage. Suppose at f
Airida [17]

Answer:

c. The steady-state value of the current depends on the resistance of the resistor.

Explanation:

Since all the components are connected in series, when the switch is at first open, current will not flow round the circuit. As current needs to flow through from the positive terminal of the battery through the resistor, inductor, and  switch to the negative terminal of the battery.

But the moment the switch is closed, at the initial time t = 0, the current flow through from the positive terminal of the battery through the resistor, inductor, and switch to the negative terminal of the battery. It then begins to increase at a rate that depends upon the value of the inductance of the inductor.

6 0
3 years ago
If a car accelerates from rest at a constant of rate of 5.5m/s^2 north, how long will it take for the car to reach a velocity of
Bingel [31]

Answer:

Explanation:

vo= 0

a=5.5m/s^2

v= 28 m/s

t=?

v=vo+at

at=v-vo

t=(v-vo)/a

t=28/5.5

t=5.09 seconds

4 0
3 years ago
Lightning flashes one mile (1609 m) away from you. How much time does it take the light to travel that distance?
hichkok12 [17]

Answer:

t=5.36\times 10^{-6}\ s

Explanation:

Given that,

Lightning flashes one mile (1609 m) away from you.

We need to find the time it take the light to travel that distance. Let the time be t. We know that,

speed = distance/time

t=\dfrac{d}{v}\\\\t=\dfrac{1609}{3\cdot10^{8}}\\\\=5.36\times 10^{-6}\ s

So, the required time is 5.36\times 10^{-6}\ s

7 0
3 years ago
An electron in a hydrogen atom undergoes a transition from the n = 3 level to the n = 6 level. To accomplish this, energy, in th
Harlamova29_29 [7]

Answer:1.816\times 10^{-19} J

Explanation:

Given

E=\frac{hc}{\lambda }

E=2.18\times 10^{-18}(\frac{1}{n_1^2}-\frac{1}{n_2^2})

where h=Planck constant

c=speed of light

E=2.18\times 10^{-18}(\frac{1}{3^2}-\frac{1}{6^2})

E=2.18\times 10^{-18}\times \frac{1}{12}

E=1.816\times 10^{-19} J

7 0
3 years ago
An object 10 cm high is placed in front of a convex mirror of focal length 20 cm and the object is 30 cm from the mirror. Find t
kotegsom [21]

Answer:

Correct option is

B

3

20

cm

Given; Focal length, f=20cm

Object distance, u=−10cm

Using mirror formula.

v

1

+

u

1

=

f

1

v

1

=

f

1

−

u

1

=

20

1

−

−10

1

(∵u=−10)

=

20

1

+

10

1

=

20

3

⇒v=

3

20

cm

6 0
3 years ago
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