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Natasha_Volkova [10]
3 years ago
11

A coin is placed on a vinyl stereo record that is making 33 1/3 revolutions per minute on a turntable. (a) In what direction is

the acceleration of the coin? (b) Find the magnitude of the acceleration when the coin is placed 5.0, 10, and 14 cm from the center of the record.
Physics
1 answer:
mamaluj [8]3 years ago
4 0

Answer: a) The acceletarion is directed to the center on the turntable. b) 5 cm; ac= 0.59 m/s^2; 10 cm, ac=1.20 m/s^2; 14 cm, ac=1.66 m/s^2

Explanation: In order to explain this problem we have to consider teh expression of the centripetal accelartion for a circular movement, which is given by:

ac=ω^2*r where ω and r are the angular speed and teh radios of the circular movement.

w=2*π*f

We know that the turntable is set to 33  1/3 rev/m so

the frequency 33.33/60=0.55 Hz

then w=2*π*0.55=3.45 rad/s

Finally the centripetal acceleration at differents radii results equal:

r= 0.05 m  ac=3.45^2*0.05=0.50 m/s^2

r=0.1  ac=3.45^2*0.1=1.20 m/s^2

r=0.14 ac=3.45^2*0.14=1.66 m/s^2

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A ray of light (f = 5.09 x 1014 Hz) is incident on the boundary between air and an unknown material X at an angle of incidence o
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Answer:

A) Material X is flint glass

B) Speed of light in the X material is 1.807 x 10^{8} m/s

C) Angle of refraction of light in medium X is 29.57^{o}

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Given data:

frequency of the light f = 5.09 x 10^{14} Hz

angle of incidence Θ_{i} = 55^{o}

index of refraction of material n_{2} = 1.66

A) To find material X

Given the index of refraction is 1.66 and hence the material is the flint glass

B) To calculate the speed of light in the material.

We know that the relation between index of refraction (n), velocity of light (c = 3 x 10^{8} m/s) and velocity of light is given by the equation:

n = c/v

Hence,

Speed of light in the X material v = c/n

                                                          = \frac{3 x 10^{8} }{1.66}

                                                          = 1.807 x 10^{8} m/s

C) To calculate angle of refraction of light in medium X

We know that the Snell's law states that

                       n_{1} sin Θ_{i}  = n_{2} sin Θ_{r}

n_{1} = incident index

n_{2}  = refracted index

Θ_{i} = incident angle

Θ_{r} = refracted angle

In given problem, n_{1} = 1 since medium is air

Substituting the known values, we get

1 x  sin 55^{o}  = 1.66 x sin Θ_{r}

sin Θ_{r} = sin 55^{o} /1.66

           = 0.4935

Hence, angle of refraction of light in medium X Θ_{r} = sin^{-1} (0.4935)

                                                                                       = 29.57^{o}

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