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alexira [117]
3 years ago
5

Find a third degree polynomial function with real coefficients and with zeros 4 and 3+i

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
3 0
X = 4 ; x = 3 + i ; x = 3 - i

(If you get a zero that is adding or subtracting, you always need to write it twice but change the sign do they cancel out)

f(x) = (x-4)(x-3-i)(x-3+i)

Distributing the last two parenthesis first is always the best way to start off

(x-3-i)(x-3+i) has (x-3) in common so it can be separated to

(x-3)^2 + (-i)(+i)

(x^2 - 6x + 9) ; (-i)(+i) is always +1
(x^2 - 6x + 9) + 1
(x^2 - 6x + 10)

Now multiply this with (x-4)
x^3 - 6x^2 + 10x
- 4x^2 + 24x - 40

x^3 - 10x^2 + 34x - 40 = f(x)

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so we know X= Numbers of Large boxes and Y= Numbers of Small boxes

And we know the large boxes weigh <em>7</em><em>5</em><em><u> </u></em><em><u>pounds</u></em> and the small boxes weigh <em>4</em><em>0</em><em> </em><em><u>pounds</u></em>

So I would have to say the the same except you have to flip the inequality sign like this:

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\geqslant  \\

200

And if that doesnt somehow work and the question is wording it wrong then

My guess for why its wrong us because its not in slope intercept form Although you still can solve for either varible ( x or y) using standard form also.

So to get from standard form to Slope intercept form (y=mx+b) these are the steps:

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75x + 40y ≤ 200

Turn it into a linear equation.

75x+ 40y =200

In order to go from one form to another, all you have to do is change the order of the given numbers. First you want to move the Ax to the opposite side of the equation, by either adding or subtracting it. At this point your equation will be set up By = -Ax + C. Then you want to divide the B from the By and the rest of the equation. Therefore you will have y = - Ax/B + C/B. This is the same thing as the slope-intercept form, just a few of the letters are different.

40y=-75x+200 first subtract 75x

y=−1.875×+5 then dived every varible (everything) by 40. and you have your Linear eqaution.

And your second question would be <em><u>A</u></em><em><u>.</u></em><em><u> </u></em><em><u>>The number of boxes must be a whole number.</u></em><em><u> </u></em>

Because you cannot split boxes in half or in any quarter in a real life scenario.

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The volume of a cylinder is 225 pi centimeters to the third and its height is 9 cm what is the length of the cylinders radius
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