Answer:
Step-by-step explanation:
I'm sorry i cant explain how i got my answer, i asked my teacher since im in geom support class at the time and she just told me the answer.
Answer:
y = 1/3 x + 5
Step-by-step explanation:
A line in slope-intercept form is written like y = mx + b, where:
"x" and "y" show points that can be on the line
"m" is the slope
"b" is the y-intercept.
If the slope is 1/3, then:
m = 1/3
If the y-intercept is 5, then:
b = 5
Substitute "m" and "b" values into the general equation.
y = mx + b
y = 1/3 x + 5
Answer:
b
Step-by-step explanation:
Answer:
It’s B)n = 2(2)"
Step-by-step explanation:
Hope this helps
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A parabola can be written with parameters:
f(x)= ax^2 + bx + c
A line can be written
f(x) = dx + e
where a, b, c, d, e are real numbers.
Now when they intersect the two functions equal eachother.
So:
ax^2+bx+c = dx +e
rearrange:
ax^2 +(b-d)x +c-e=0
Lets call b-d=f and c-e=g, (f, g are still real numbers)
We get:
ax^2+fx+g=0
Now this is the standard form of 2nd degree polynomial. And we know that this can have 0,1,2 real solutions.
Thus we have proven that they cannot have more than 2 points of intersection.