Well first 9450/5=1890 then 1890/6= 315 watt hours per day
Answer:
55/43
Step-by-step explanation:
(x/y) = 7/3, (x^2/y^2)=49/9, multiply by 3 above and multiply 2 below, 3x^2/2y^2=147/18. Next apply C&D and you will get (3x^2+2y^2)/(3x^2-2y^2)=(147+18)/(147-18)=165/129=55/43
2(8-4)^2-5
16-32-5
-21
you can change the -10/2 to a -5 and it will be easier.

The required values are ~
Refer to attachment for solution ~