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ale4655 [162]
3 years ago
10

Which decimals are less than 2.312 select all that apply A. 2.311. B.2.4 C.2.32 D.2.3 E.2.31 F.2.313

Mathematics
2 answers:
Kaylis [27]3 years ago
5 0

Answer:

a d e

Step-by-step explanation:

fgiga [73]3 years ago
3 0

Answer:

A, D, E

Step-by-step explanation:

I hope this is correct

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Find the area of this circle. Use 3 for a.A = 7r2=11 in[?] in?
liberstina [14]

SOLUTION

We want to find the area of the circle in the picture given.

We have been given the formula as

\begin{gathered} A=\pi r^2 \\ We\text{ are told to take }\pi\text{ as 3} \\  \end{gathered}

From the circle, the radius r = 11 in.

The area of the circle becomes

\begin{gathered} A=\pi r^2 \\ A=\pi\times r^2 \\ A=3\times11^2 \\ A=3\times11\times11 \\ A=363in^2 \end{gathered}

Hence the answer is 363 square-inches

7 0
10 months ago
It says to find the area of the figure but I have no idea what to do
Westkost [7]
2.5 is also on the top and try multiplying 2.5 and 10
6 0
2 years ago
The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?
omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

T_5 = 160

T_7 = 40

Required

T_6

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

\frac{T_7}{T_5} = \frac{40}{160}

Divide the numerator and the denominator of the fraction by 40

\frac{T_7}{T_5} = \frac{1}{4} ----- equation 1

Recall that the formula of a GP is

T_n = a r^{n-1}

Where n is the nth term

So,

T_7 = a r^{6}

T_5 = a r^{4}

Substitute the above expression in equation 1

\frac{T_7}{T_5} = \frac{1}{4}  becomes

\frac{ar^6}{ar^4} = \frac{1}{4}

r^2 = \frac{1}{4}

Square root both sides

r = \sqrt{\frac{1}{4}}

r = ±\frac{1}{2}

Next, is to solve for the first term;

Using T_5 = a r^{4}

By substituting 160 for T5 and ±\frac{1}{2} for r;

We get

160 = a \frac{1}{2}^{4}

160 = a \frac{1}{16}

Multiply through by 16

16 * 160 = a \frac{1}{16} * 16

16 * 160 = a

2560 = a

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

T_n = a r^{n-1}

Here, n = 6;

T_6 = a r^{6-1}

T_6 = a r^5

T_6 = 2560 r^5

r = ±\frac{1}{2}

So,

T_6 = 2560( \frac{1}{2}^5) or T_6 = 2560( \frac{-1}{2}^5)

T_6 = 2560( \frac{1}{32}) or T_6 = 2560( \frac{-1}{32})

T_6 = 80 or T_6 = -80

T_6 =±80

Hence, the 6th term is positive/negative 80

8 0
3 years ago
-18+-6 please help
Verdich [7]

Answer:

-24

Step-by-step explanation:

If you are struggling with this here's a tip!

-18+-6 is what you are trying to solve

The 6 is negative, so get rid of the plus sign -18-6

2 negative numbers are just added like positive numbers

So add 18 and 6, you should get 24

Don't forget about the negative!

-24

6 0
2 years ago
1) A line has a slope of -2 and passes through the points A(x,5), B(4,-5) and C(6,y). Find the coordinates of A and C.
siniylev [52]
1) Coordinates of A: (-1,5)  Coordinates of C: (6,-9)

2) Coordinates of A: (-1,-14) Coordinates of M: (6,7)


3 0
3 years ago
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