50%. students (in percent) who passed the second exam also passed the first exam.
Let's imagine that there are 100 kids in the teacher's class. We know that 40 of them passed BOTH tests, and 80 passed the second test.
Because if they weren't, they wouldn't have passed the first test and consequently wouldn't have passed both, we can be sure that the group of students who passed BOTH tests is only made up of the 80 who passed the second test.
Thus, both tests were passed by 40 of the 80 pupils who passed the second one:
40/80 = 1/2 = 50%.
Find out more on Percentage at:
brainly.com/question/24877689
#SPJ4
The answer is 1A definitely
Answer:
X=7
Step-by-step explanation:
X = SQRT(49)
X = 7
Best regards
Answer:
The probability of getting a factor of 12 on a fair dice is 5/6 or approximately 83%.
Step-by-step explanation:
Probability is expressed as a fraction where the denominator is the total number of outcomes and the numerator is the number of desired outcomes. In this case, the desired outcome is any factor of 12. The factors of 12 are the numbers we multiply together to get that number: 1, 2, 3, 4, 6 and 12. Since a fair dice has the total outcomes of either 1, 2, 3, 4, 5 or 6, then the total outcomes is 6 and the possibility that we could roll the desired outcome (factor of 12) is 5, the probability is 5 out of 6 or 5/6, which when divided is approximately 83%.
