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ladessa [460]
3 years ago
10

Fred and his family went to the zoo. Fred started the day with $100. He bought 2 adult tickets for

Mathematics
1 answer:
bogdanovich [222]3 years ago
8 0

Answer:

23

Step-by-step explanation:

100-(2)15=70

70-(3)8=46

46/2 =23

You might be interested in
How many g of amino acids are in a 2,000mL total parenteral nutrition of 4.25% travesol (amino acids and 20%dextrose?
kirill115 [55]

Answer:

The  mass of  amino acid present is  85 g

Step-by-step explanation:

From the question we are told that

   The  volume of the total  parenteral nutrition is  V  =  2000 mL

   

Generally the volume of the amino acid present is  

                V_a =  0.0425 *  2000

                V_a =  85 mL

Generally  

               mass  \ \ \alpha  \ \ volume

So the mass of amino acid present is 85g

6 0
3 years ago
If Jefferson is drawing cards from a deck, and draws a 4 of hearts and a 10 of diamonds, what is this situation considered?
katrin2010 [14]
<h3>Answer:  A) Outcome</h3>

==========================================================

Explanation:

We can rule out "theoretical probability" since that concept deals with doing the math on paper, rather than getting out an actual deck of cards to compute the probability. If your teacher stated "the probability of drawing an ace is 1/13", then s/he would be using theoretical probability. We have a 1 in 13 chance to theoretically pick an ace out of all 52 cards since 4/52 = 1/13. No cards are needed to do such calculations. But if you actually pull out a deck of cards and randomly select them, then you'd be leaning toward empirical or experimental probability.

So in short, we can rule out choice B.

We can also rule out "complement" since the two situations of "drawing a 4" and "drawing a 10" aren't opposite. If it said something like "drawing a red card or drawing a black card", then those two events are opposite. The two events fully compose all the deck of cards (sample space). You either will draw a red one, or a black one, but not both colors at the same time.

So we're down to the answer being either A) outcome or D) event. At first glance, these two terms seem almost identical. However, they mean slightly different things.

Let's pick apart what each of those terms mean.

----------------

The outcome is the result of an event. An event is some specific action that you may or may not want to happen, and it's usually phrased within the parameters your teacher set up.

For example, we can define the event "it rains outside". So we're setting up the specific action of raining. Whether we want it or not doesn't really matter. The outcome would be the actual result of if the event happens or not. So if it does truly rain on day 1, then the outcome "rain" is what is recorded for day 1. Then if its dry on day 2, then "no rain" is the outcome for that second day. And so on.

Going back to the cards, one event could be set up as "selecting a heart card" with the outcome being "selected a 4 of hearts". The event is the rule set up and the outcome is the result we observe. To compute the empirical or experimental probability, we divide the number of times we get a specific event to occur over the total number of possible

---------------

Let's look at another example.

We'll roll a single die that has 6 faces on it. The set of possible outcomes are {1,2,3,4,5,6}. Only one outcome is possible per roll.

If we roll the die and it lands on 5, then the outcome is 5. This is the final result of the trial or experiment.

We can define an event like "A = rolling an even number", and then ask the question "what is the probability event A occurs?" In other words, we would be asking "what is the probability of rolling an even number?"

---------------

I suppose now that I think about it, we can state,

  • outcome = some single action you observe
  • event = collection of outcomes (usually some pattern to it)

as a loose way of telling the difference between the two terms.

Ultimately, the observations of getting a 4 of hearts and 10 of diamonds are considered an outcome.

4 0
3 years ago
One hundred twenty-three and thirty hundreths. in decimal form
Doss [256]

Answer:

123.030

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
a new line is drawn through the point (-3,6) and perpendicular to the line with x-intercept (3,0) and y intercept (0,3) . what i
Klio2033 [76]

Answer:

The equation of the new line is y=x+9  or  y-6=(x+3)

Step-by-step explanation:

step 1

Find out the slope of the line with x-intercept (3,0) and y intercept (0,3)

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the values

m=\frac{3-0}{0-3}=-1

step 2

Find the slope of the new line perpendicular to the given line

we know that

If two lines are perpendicular,then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

m_1*m_2=-1

we have

m_1=-1 ----> slope of the given line

so

m_2=1 ---> slope of the new line

step 3

Find the equation of the new line in point slope form

y-y_1=m(x-x_1)

we have

m=1

(x_1,y_1)=(-3,6)

substitute

y-6=(1)(x+3)

y-6=(x+3) ----> equation in point slope form

Convert to slope intercept form

y=mx+b

isolate the variable y

y=x+3+6

y=x+9

6 0
2 years ago
Find, corrrect to the nearest degree, the three angles of the triangle with the given vertices. A(1,0), B(3,6), C(-1,4)
Karo-lina-s [1.5K]

Answer:

45°, 45°, 90°

Step-by-step explanation:

Find the vectors to represent each sides

AB =<3-1, 6-0>=<2,6>  

AC = < -1-1, 4 - 0 > = < -2, 4>

Magnitude of the vectors

AB = √(2²+6²) = 6.32

AC = √ ((-2)² + 4²) = 4.47

cosθ = vector of AB × vector AC / ( Product of the magnitude of AB and AC) = 2 × (-2) + (6×4)/ (6.32×4.47) = 20 / 28.2504

θ = arcos(20 / 28.2504 ) approx = 45°

Magnitude of the vectors

BA =<1-3,0-6>=<-2,-6>

BC =<-1-3,4-6>=<-4,-2>

Magnitude of the vectors equals

BA = √((-2)² + (-6)²) = 6.325

BC = √((-4)² + (-2)²) = 4.4721

cosθ = (-2×-4) + (-6 ×-2) / (6.325 × 4.4721) = 20 / 28.286

θ  = arcos (20 / 28.286 ) = 45°

Magnitude of the vectors

CB =<3--1, 6-4>=<4,2>

CA=<1--1,0-4>=<2,-4>

Magnitude of the vector =

CB = √(4² + 2²) = 4.4721

CA = √(2² + (-4)²) = 4.4721

cosθ = (4×2) + (2×-4) / (4.4721×4.4721) = 0

θ = arcos 0 = 90°

4 0
3 years ago
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