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EleoNora [17]
3 years ago
11

The following table shows the percent increase of donations made on behalf of a non-profit organization for the period of 1984 t

o 2003. Use a graphing calculator to make a scatter plot of the data. Find an equation for and graph the line of regression. Then use the equation to predict the percent donated in the year 2015. 

Year
1984
1989
1993
1997
2001
2003
Percent
187.9 213.9 234.7 255.5 276.3 286.7

Mathematics
1 answer:
Art [367]3 years ago
8 0
In this problem, the dependent variable is the time or the year while the independent variable is the percent increase of donations. We try to plot these data through the years (percent increase vs year) in MS Excel and then obtain the trendline equation. Attached is the graph drawn from the data provided. According to the software, the equation applicable to this data is y = 5.2x - 10129 in which R² = 1. This means the relationship between the two variables is linear and perfect. The slope is positive which means that as the year goes on, the percent increase in donations also increases.

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Change 7 out of 50 into a percentage and change 18 out of 20 into a percentage
Ksivusya [100]
7/50 = 0.14
0.14 x 100 = 14
14%

18/20 = 0.9
0.9 x 100 = 90
90%
3 0
3 years ago
Which statement is true?​
love history [14]
<h2>Hello!</h2>

The answer is:

The second option,

(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }

<h2>Why?</h2>

Discarding each given option in order to find the correct one, we have:

<h2>First option,</h2>

\sqrt[m]{x}\sqrt[m]{y}=\sqrt[2m]{xy}

The statement is false, the correct form of the statement (according to the property of roots) is:

\sqrt[m]{x}\sqrt[m]{y}=\sqrt[m]{xy}

<h2>Second option,</h2>

(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }

The statement is true, we can prove it by using the following properties of exponents:

(a^{b})^{c}=a^{bc}

\sqrt[n]{x^{m} }=x^{\frac{m}{n} }

We are given the expression:

(\sqrt[m]{x^{a} } )^{b}

So, applying the properties, we have:

(\sqrt[m]{x^{a} } )^{b}=(x^{\frac{a}{m}})^{b}=x^{\frac{ab}{m}}\\\\x^{\frac{ab}{m}}=\sqrt[m]{x^{ab} }

Hence,

(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }

<h2>Third option,</h2>

a\sqrt[n]{x}+b\sqrt[n]{x}=ab\sqrt[n]{x}

The statement is false, the correct form of the statement (according to the property of roots) is:

a\sqrt[n]{x}+b\sqrt[n]{x}=(a+b)\sqrt[n]{x}

<h2>Fourth option,</h2>

\frac{\sqrt[m]{x} }{\sqrt[m]{y}}=m\sqrt{xy}

The statement is false, the correct form of the statement (according to the property of roots) is:

\frac{\sqrt[m]{x} }{\sqrt[m]{y}}=\sqrt[m]{\frac{x}{y} }

Hence, the answer is, the statement that is true is the second statement:

(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }

Have a nice day!

6 0
3 years ago
identify the amplitude and period of the function then graph the function and describe the graph of G as a transformation of the
mrs_skeptik [129]

Given the function:

g(x)=cos4x

Let's find the amplitude and period of the function.

Apply the general cosine function:

f(x)=Acos(bx+c)+d

Where A is the amplitude.

Comparing both functions, we have:

A = 1

b = 4

Hence, we have:

Amplitude, A = 1

To find the period, we have:

\frac{2\pi}{b}=\frac{2\pi}{4}=\frac{\pi}{2}

Therefore, the period is = π/2

The graph of the function is shown below:

The parent function of the given function is:

f(x)=cosx

Let's describe the transformation..

Apply the transformation rules for function.

We have:

The transformation that occured from f(x) = cosx to g(x) = cos4x using the rules of transformation can be said to be a horizontal compression.

ANSWER:

Amplitude = 1

Period = π/2

Transformation = horizontal compression.

8 0
1 year ago
21-x=13 telllllllllll mee​
BaLLatris [955]

Answer:

x = 8

Step-by-step explanation:

21-x=13 \\ x = 21 - 13 \\ x = 8

4 0
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Mamont248 [21]

Answer: 5?

Step-by-step explanation:

there are 5 prizes to be chosen from.

4 0
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