All categories

3 years ago

What is 180 divided by 20,835

Mathematics

2 answers:

ohaa [14]3 years ago

4 0

0.00863930885. Hope this helps you.

grigory [225]3 years ago

3 0

$\frac{180}{20,835} = \frac{4}{463} = 0.00863930885$

You might be interested in

SOMEONE PLEASE HELP ME I DONT KNOW HOW TO DO THIS AT ALL

Lina20 [59]

Answer:

$y=2cos(4\pi x)\\
$

Step-by-step explanation:

Since the amplitude of the cosine function is 2, I would put the multiply it by 2. There is no phase shift

The period is 1/2, so it would be 4pi

Plug them in into y=Acos(Bx), y=2cos(4pix)

6 0

2 years ago

I don't understand. Please help answer questions!!!!!!

insens350 [35]

16) yes, they are reflections on a summit.
17) no parallelogram shown to answer question

7 0

3 years ago

Light shines through window what is the area of a trapezoid shaped region created by the light

bogdanovich [222]

Answer:

16 ft²

Step-by-step explanation:

The complete question is attached.

A trapezoid is a quadrilateral (has four sides) with one a parallel base. The base angles and the diagonals of an isosceles trapezoid are equal.

The area of a trapezoid = [(sum of the parallel bases) / 2] * height of the trapezoid.

Given that the parallel bases are 3 ft and 5 ft, while the height of the trapezoid is 4 ft. Hence:

The area of a trapezoid = [(3 + 5)/2] * 4

The area of a trapezoid = 16 ft²

5 0

3 years ago

Answer the questions below about the quadratic function.

Korolek [52]

Given the function $f(x)=3x^2-18x+23$ . The above function can be written as

$f(x)=3x^2-18x+23\\ f(x)=3(x^2-6x)+23\\ f(x)=3(x^2-6x+9-9)+23\\ f(x)=3(x-3)^2-27+23\\ f(x)=3(x-3)^2-4$

a)Now, the function $f(x)=3(x-3)^2-4$ has minimum value since the coefficient of $(x-3)^2$ is $3>0$ .

b) The minimum value of the function occurs at $x=3$ and its value is

$f(3)=3(3-3)^2-4 =-4$

c)The minimum value of the function occurs at $x=3$ .

6 0

3 years ago

Determine whether the set of vectors is a basis for ℛ3. Given the set of vectors , decide which of the following statements is t

schepotkina [342]

Answer:

(A) Set A is linearly independent and spans $R^3$ . Set is a basis for $R^3$ .

Step-by-Step Explanation

Definition (Linear Independence)

A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.

Definition (Span of a Set of Vectors)

The Span of a set of vectors is the set of all linear combinations of the vectors.

Definition (A Basis of a Subspace).

A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.

Given the set of vectors $A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right)$ , we are to decide which of the given statements is true:

In Matrix $A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right)$ , the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. $R^3$ has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans $R^3$ .

Therefore Set A is linearly independent and spans $R^3$ . Thus it is basis for $R^3$ .

8 0

3 years ago