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natulia [17]
3 years ago
5

What is log 5 + log 2?

Mathematics
2 answers:
olganol [36]3 years ago
6 0
The answer is one if you have a graphing calculator
Licemer1 [7]3 years ago
5 0
Hey!~ 

Log 5 + Log 2 = 1

Hope this helps and have a nice day!

-Lindsey
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A 64-inch board is cut into three pieces so that the second piece is twice as long as the first piece, and the third
Dafna1 [17]
<h3>Answer:  40 inches</h3>

==========================================================

Explanation:

  • x = first piece
  • 2x = second piece, since its twice as long as the first
  • 5x = third piece, since its five time as long as the first

x is some positive real number, and the units of each are in inches.

Add up the smaller pieces and we should get 64 inches back again

x+2x+5x = 64

8x = 64

x = 64/8

x = 8

The first piece is 8 inches long.

2x = 2*8 = 16 is the length of the second piece (in inches)

The third piece is 40 inches because 5x = 5*8 = 40

--------

Summary:

first = 8 inches

second = 16 inches

third = 40 inches

Check: 8+16+40 = 64, which confirms the answer

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3 years ago
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My name is Ann [436]

Answer: Cya

Step-by-step explanation:

4 0
3 years ago
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A certain article indicates that in a sample of 1,000 dog owners, 610 said that they take more pictures of their dog than of the
lbvjy [14]

Answer:

(a) The 90% confidence interval is: (0.60, 0.63) Correct interpretation is (3).

(b) The 95% confidence interval is: (0.42, 0.46) Correct interpretation is (1).

(c) First, the confidence level in part(b) is <u>more than</u> the confidence level in part(a) is, so the critical value of part(b) is <u>more than</u> the critical value of part(a), Second the <u>margin of error</u> in part(b) is <u>more than</u> than in part(a).

Step-by-step explanation:

(a)

Let <em>X</em> = number of dog owners who take more pictures of their dog than of their significant others or friends.

Given:

<em>X</em> = 610

<em>n</em> = 1000

Confidence level = 90%

The (1 - <em>α</em>)% confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

The sample proportion is:

\hat p=\frac{X}{n}=\frac{610}{1000}=0.61

The critical value of <em>z</em> for a 90% confidence level is:

z_{\alpha/2}=z_{0.10/2}=z_[0.05}=1.645

Construct a 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends as follows:

CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.61\pm 1.645\sqrt{\frac{0.61(1-0.61}{1000}}\\=0.61\pm 0.015\\=(0.595, 0.625)\\\approx(0.60, 0.63)

Thus, the 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends is (0.60, 0.63).

<u>Interpretation</u>:

There is a 90% chance that the true proportion of dog owners who take more pictures of their dog than of their significant others or friends falls within the interval (0.60, 0.63).

Correct option is (3).

(b)

Let <em>X</em> = number of dog owners who are more likely to complain to their dog than to a friend.

Given:

<em>X</em> = 440

<em>n</em> = 1000

Confidence level = 95%

The (1 - <em>α</em>)% confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

The sample proportion is:

\hat p=\frac{X}{n}=\frac{440}{1000}=0.44

The critical value of <em>z</em> for a 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Construct a 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend as follows:

CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.44\pm 1.96\sqrt{\frac{0.44(1-0.44}{1000}}\\=0.44\pm 0.016\\=(0.424, 0.456)\\\approx(0.42, 0.46)

Thus, the 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend  is (0.42, 0.46).

<u>Interpretation</u>:

There is a 95% chance that the true proportion of dog owners who are more likely to complain to their dog than to a friend falls within the interval (0.42, 0.46).

Correct option is (1).

(c)

The confidence interval in part (b) is wider than the confidence interval in part (a).

The width of the interval is affected by:

  1. The confidence level
  2. Sample size
  3. Standard deviation.

The confidence level in part (b) is more than that in part (a).

Because of this the critical value of <em>z</em> in part (b) is more than that in part (a).

Also the margin of error in part (b) is 0.016 which is more than the margin of error in part (a), 0.015.

First, the confidence level in part(b) is <u>more than</u> the confidence level in part(a) is, so the critical value of part(b) is <u>more than</u> the critical value of part(a), Second the <u>margin of error</u> in part(b) is <u>more than</u> than in part(a).

4 0
2 years ago
HELP!!!!PLS!!
chubhunter [2.5K]

Answer:

12 units

Step-by-step explanation:

(-7,-6)

if you reflect it over the x-axis then the second number would be changing

-6 the opposite is 6

(-7, 6)

from -6 to 6 is 12 jumps

12 units is the distance from the original point

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3 years ago
Alayaa crashed her car through a fence, ran over a garbage can and ran into a tree. The fence will cost $550 to repair, $50 to r
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She'll have to pay 20,605
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3 years ago
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