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SSSSS [86.1K]
3 years ago
8

Pairs of integers with a product of 48

Mathematics
2 answers:
worty [1.4K]3 years ago
8 0

   48

   ∧

1     48   →     1, 48    and     -1, -48

2    24   →     2, 24   and     -2, -24

3    16    →     3, 16    and     -3, -16

4    12    →     4, 12    and     -4, -12

5    X

6    8     →     6, 8    and     -6, -8

7    X

LekaFEV [45]3 years ago
6 0
(-2)(-24)
(-3)(-16)
(-4)(-12)
(-6)(-8)
-(-1)(-48)

1*48
2*24
3*16
4*12
6*8
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3 years ago
If N is the population of the colony and t is the time in​ days, express N as a function of t. Consider Upper N 0 is the origina
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Answer:

(a)N(t)=Noe^{kt}

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(c)5 days

Step-by-step explanation:

(a)Given an original amount N_o at t=0. The population of the colony with a growth rate k \neq 0, where k is a constant is given as:

N(t)=Noe^{kt}

(b)If N_o=1000 and the population after 1 day, N(1)=1800

Then, from our model:

N(1)=1800

1800=1000e^{k}\\$Divide both sides by 1000\\e^{k}=1.8\\$Take the natural logarithm of both sides\\k=ln(1.8)

Therefore, our model is:

N(t)=1000e^{t*ln(1.8)}\\N(t)=1000\cdot1.8^t

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N(3)=1000\cdot1.8^3=5832

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(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.

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N(t)=1000\cdot1.8^t\\20000=1000\cdot1.8^t\\$Divide both sides by 1000\\20=1.8^t\\$Convert to logarithm form\\Log_{1.8}20=t\\\frac{Log 20}{Log 1.8}=t\\ t=5.097\approx 5\; days

In approximately 5 days, the population of mosquitoes will be 20,000.

7 0
2 years ago
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