10 1/2 x 2 2/3= 28, 3 1/3 x 4 2/7= 14.2857142857, 7/2 - 4/5= 2.7
The real solutions the equation as given in the task content; x² = 225 are; +25 and -25.
<h3>What are the real solutions of the equation as given in the task content?</h3>
It follows from the task content that the real solutions of the equation as given in the task content can be determined as follows;
x² = 225
x = ± 15
Therefore, the real solutions of the equation are; +25 and -25.
Read more on real solutions of equations;
brainly.com/question/3122484
#SPJ1
Just multiple them together and u get 693
πAnswer:
Therefore, the area of a sector of a circle would be 13.5π square units.
Step-by-step explanation:
Given
mi
The area of a sector of a circle is:
A = π r² Ф/360
A = π (9)² 60/360
A = π 81 * 1/6
A = 13.5π square units
Therefore, the area of a sector of a circle would be 13.5π square units.
