G(x)=-x+0. Any equation reflected across the x axis will have the opposite x value as the original function. Hope this helps!
(f(x) in red, g(x) in blue)
A. (f + g)(x) = f(x) + g(x) = 4x - 5 + 3x + 9 = 7x + 4
B. f.g (x) = f(x) * g(x) = (4x - 5)*(3x + 9) = 12x^2 + 36x - 15x - 45
= 12x^2 + 21x - 45
C Replace the x in f(x) by g(x):-
= 4(3x + 9) - 5
= 12x + 36 - 5
= 12x + 31
Answer:
B
Step-by-step explanation:
For this case, the first thing we must do is take into account the definition of the axes:
the x axis is time in seconds
the y axis is velocity in meters per secon
Then, we look for the cut point with the y axis, which is given by:
(0, 2)
This means that the initial speed is 2 m / s.
We now look for the cut point with the x axis, which is given by:
(8, 0)
This means that the speed is 0 m / s, so the runner stopped when the time is 8 seconds.
Answer:
The initial velocity of the runner was 2 m / s, and the runner stopped after 8 seconds.
Ur not dumb!!! i graphed the line for u here. i suggest watching some khan academy videos for extra practice!
