Answer:
The GCF of the coefficients is correct.
The variable c is not common to all terms, so a power of c should not have been factored out.
In step 6, David applied the distributive property.
Step-by-step explanation:
Given the polynomial :
80b⁴ – 32b²c³ + 48b⁴c
The Greatest Common Factor (GCF) of the coefficients:
80, 32, 48
Factors of :
80 : 1, 2, 4, 5, 8, 10, 16, 20, 40, and 80
32 : 1, 2, 4, 8, 16, and 32
48 : 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48.
GCF = 16
b⁴, b², b⁴
b⁴ = b * b * b * b
b² = b * b
b⁴ = b * b * b * b
GCF = b*b = b²
GCF of c³ and c
c³ = c * c * c
c = c
GCF = c
We can see that David's GCF of the coefficients are all correct
From the polynomial ; 80b⁴ does not contain c ; so factoring out c is incorrect
In step 6 ; the distributive property was used to obtain ; 16b²c(5b² – 2c² + 3b²)
