Answer:
(-3, 1) quadrant II (2)
Step-by-step explanation:
An image of the coordinate plane is show. The quadrants start at the top right and move around in the counter-clockwise direction. The x-axis is horizontal (side to side) and y-axis is vertical (up and down). Starting at the origin of the coordinate plane (0, 0) and going three blocks west (left) would put you at -3 on the x-axis. If you then proceed to go north (up) +1, you would now be at point (-3, 1) which is a (-x, +y) or in quadrant II.
Answer:
7x(2y+3)
Step-by-step explanation:
F(x) means the function defined at that x value. It really just means what y value when x is equal to that input. So we can see clearly that A is false. They’re nearly opposite y values. B is also obviously false since the y values aren’t equal. C is the same case, the y values aren’t equal. D is true. When x = -2 for both functions, we can see the y value is the same. They also intercept, so that’s a pretty dead giveaway
D.)
Answer:
The probability is 0.3576
Step-by-step explanation:
The probability for the ball to fall into the green ball in one roll is 2/1919+2 = 2/40 = 1/20. The probability for the ball to roll into other color is, therefore, 19/20.
For 25 rolls, the probability for the ball to never fall into the green color is obteined by powering 19/20 25 times, hence it is 19/20^25 = 0.2773
To obtain the probability of the ball to fall once into the green color, we need to multiply 1/20 by 19/20 powered 24 times, and then multiply by 25 (this corresponds on the total possible positions for the green roll). The result is 1/20* (19/20)^24 *25 = 0.3649
The exercise is asking us the probability for the ball to fall into the green color at least twice. We can calculate it by substracting from 1 the probability of the complementary event: the event in which the ball falls only once or 0 times. That probability is obtained from summing the disjoint events: the probability for the ball falling once and the probability of the ball never falling. We alredy computed those probabilities.
As a result. The probability that the ball falls into the green slot at least twice is 1- 0.2773-0.3629 = 0.3576
