Question

Which equation can be used to represent "three minus the difference of a number and one equals one-half of the difference of three times the same number and four”?
(1 – n) – 3 = (4 – 3n)
3 – (1 – n) = (4 – 3n)
(n – 1) – 3 = (3n – 4)
3 – (n – 1) = (3n – 4)

Answer 1

Answer:

Let the number be n.

Given: "three minus the difference of a number and one equals one-half of the difference of three times the same number and four"

then,

The expression "three minus the difference of a number and one" represent the equation is;  

$3 -(n-1)$

And

The expression "one-half of the difference of three times the same number and four" represent the equation  is;

$\frac{1}{2}(3n-4)$

therefore,

the complete expression represents the equation is;

$3-(n-1)=\frac{1}{2}(3n-4)$

Answer 2

Answer:

$3-(n-1)=\frac{1}{2}(3n-4)$

Step-by-step explanation:

We will go by the statements given in the question.

If a number is n then

"Three minus the difference of a number and one" will be [3 - ( n - 1)]

" Difference of one half of three times the same number and four" will be $\frac{1}{2}(3n-4)$

Now both the statements are equal.

$3-(n-1)=\frac{1}{2}(3n-4)$

Therefore the answer of the question will be

$3-(n-1)=\frac{1}{2}(3n-4)$.