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harkovskaia [24]
3 years ago
13

PLS HELP ME ASAP ON COMPLETING THE COMBINATION CHART, OR ENOUGH TO ANSWER QUESTION “D”

Mathematics
1 answer:
Kitty [74]3 years ago
5 0
In the table and chart, we have let x represent numbers of Rock CDs and y represent numbers of Rap CDs.

a) The purple dots represent feasible solutions. Their coordinates are listed in the table (for coordinates on the lines) and as a list of points (for points between the lines).

b) The feasible region for total time in hours is shaded blue.

c) The feasible regiion for total cost is shaded red.

d) The overlap of the two regions is shaded purple. The combinations that are feasible are purple dots in that region.

e) The equations used are listed at the left side of the chart. The equations are labeled by color. (≤112 is the cost equation; ≥75 is the hours equation)

ea) The area that is feasible with respect to both constraints is doubly-shaded.

eba) Too much money is spent to the right of the red line.
ebb) Too few hours are used to the left of the blue line.

f) The line for the desired profit is parallel to the "hours" line, but has x-intercept 10 and y-intercept 6. All the points shown except the two on the lower line will give the desired profit.

g) The higher profit line goes through the points (3, 7) and (8, 4). Those two combinations and the points on or near the upper line above y=4 will meet the higher profit requirement.

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16. Tell whether the lines for each pair of equations are parallel, perpendicular, or neither.
il63 [147K]

Answer:

Given equation are:

y = -\frac{1}{4}x+8                  ......[1]

-2x+8y = 4                             .....[2]

  • The two lines are parallel lines then their slopes will be equal.
  • When two lines are perpendicular then, the slope of lines are the negative reciprocals of each other.

Now, Equation of a line is in the form of y =mx+b where m is the slope of the line.

Slope(m_1) of equation of line in [1] is;

y = -\frac{1}{4}x+8  

then;

m_1= -\frac{1}{4}

Slope(m_2) of equation of line in [2];

-2x+8y = 4

Add both sides 2x we get;

-2x + 8y + 2x = 2x + 4

Simplify:

8y = 2x +4

Divide both sides by 8 we get;

y = \frac{1}{4} x + \frac{1}{2}

then;

m_2 = \frac{1}{4}

Therefore, the given two lines are neither parallel nor perpendicular.

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