PLEASE HELP ASAP!!!!!

3. Formulate 900 lbs of a 35% CP ration using Soybean Meal (46% CP) and Oats (12% CP). How many pounds of soybean meal will be u

Anarel [89]

Answer:

The amount of Soyabean = 608.82 pounds.

The amount of Oats = 900-608.82 = 291.18 pounds.

Step-by-step explanation:

Given that the Soybean Meal has 46% CP and Oats has 12% CP.

The total amount of ration is 900 lbs of 35% CP.

Let x pounds of Soyabean has been used, so,

the amount of Oats = 900-x lbs.

The CP amount in 900 lbs mixture will be equal to the sum of CP amounts in x lbs Soyabean and 900-x lbs Oats, i.e

35% of 900 = 46% of x + 12% of (900-x)

$\Rightarrow \frac{35}{100}\times 900=\frac{46}{100}\times x+\frac{12}{100}\times (900-x)$

$\Rightarrow 35\times 900 = 46x + 12\times 900 - 12 x$

$\Rightarrow 34x= 900(35-12)$

$\Rightarrow x = (900\times 23)/34$

$\Rightarrow x = 608.82$ lbs.

So, the amount of Soyabean = 608.82 pounds.

The amount of Oats = 900-608.82 = 291.18 pounds.

5 0

2 years ago

Consider the example of finding the probability of selecting a black card or a 6 from a deck of 52 cards.

Marina86 [1]

Answer:

The probability of selecting a black card or a 6 = 7/13

Step-by-step explanation:

In this question we have given two events. When two events can not occur at the same time,it is known as mutually exclusive event.

According to the question we need to find out the probability of black card or 6. So we can write it as:

P(black card or 6):

The probability of selecting a black card = 26/52

The probability of selecting a 6 = 4/52

And the probability of selecting both = 2/52.

So we will apply the formula of compound probability:

P(black card or 6)=P(black card)+P(6)-P(black card and 6)

Now substitute the values:

P(black card or 6)= 26/52+4/52-2/52

P(black card or 6)=26+4-2/52

P(black card or 6)=30-2/52

P(black card or 6)=28/52

P(black card or 6)=7/13.

Hence the probability of selecting a black card or a 6 = 7/13 ....

7 0

3 years ago

1.) A 20° sector in a circle has an area of 21.5π yd².

a_sh-v [17]

Part 1) A 20° sector in a circle has an area of 21.5π yd².

What is the area of the circle?

we know that

the area of a circle represent a sector of $360$ degrees

so by proportion

$\frac{21.5\pi }{20} =\frac{x}{360} \\ \\ x*20=360*21.5\pi \\ \\x=(360*21.5*3.14)/20\\ \\x= 1,215.18\ yd^{2}$

therefore

the answer part 1) is

The area of the circle is $1,215.18\ yd^{2}$

Part 2) What is the area of a sector with a central angle of 3π/5 radians and a diameter of 21.2 cm?

we know that

the area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

in this problem we have

$Diameter=21.2\ cm\\ r=Diameter/2\\r=21.2/2\\r= 10.6\ cm$

Find the area of the circle

$A=\pi r^{2}$

$A=\pi*10.6^{2}$

$A=352.8104\ cm^{2}$

Find the area of the sector

we know that the area of the circle represent a sector of $2\pi$ radians

by proportion

$\frac{352.8104}{2\pi }=\frac{x}{(3\pi/5)} \\\\x*2\pi=(3\pi*352.8104)/5\\ \\x= 105.84\ cm^{2}$

therefore

the answer part 2) is

the area of the sector is

$105.84\ cm^{2}$

7 0

3 years ago

Y=40+90x what is the meaning

Dafna1 [17]

Y = total cost
40 = The one time fee
90 = the service charge per month
x = number of months

4 0

4 years ago

A bottle of medicine contains 40 doses. How many doses are in 3 1/3 bottles?

sdas [7]

Hi there! So, there are 40 doses in 1 bottle. To find out the number of doses in 3 1/3 bottles, we have to multiply both numbers together. 3 1/3 as an improper faction is 10/3. 40/1 * 10/3 is 400/3 or 133 1/3 in simplest form. There are 133 1/3 doses of medicine in 3 1/3 bottles.

7 0

3 years ago