0.30/1.50= 0.2= 20%
20%<span> of 1.50 = 0.30</span>
Answer: pretty sure the answer is D
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given
Required
The average rate over ![[2,b]](https://tex.z-dn.net/?f=%5B2%2Cb%5D)
Average rate (m) is calculated using:
Where
![[a,b] = [2,b]](https://tex.z-dn.net/?f=%5Ba%2Cb%5D%20%3D%20%5B2%2Cb%5D)
So, we have:
Calculate f(b) and f(2)
So, we have:
Expand the numerator
Factorize
Factor out 3b + 6
Cancel out b - 2
Answer:
(a) AC = 12.565 m
(b) bearing of C from A is 90°
(c) BT = 9.373 m
Step-by-step explanation:
(a) extend North line down & perpendicular to AC.
Call that perpendicular intersection "P".
∠BAC = 90° - 53° = 37°
cos 37° = AP/15
0.7986 = AP/15
AP = 11.979 m
∠PNC = 180° - 161° = 19°
∠BCP = 90° - 19° = 71°
18 cm = 0.18 m (red flag note: 18 cm looks very out of scale for the picture)
cos 71° = CP/0.18
0.3256 = CP/0.18
CP = 0.586 m
AC = 11.979 + 0.586 = 12.565 m
(b) The bearing to C from A is 90°
(c) tan 58° = 15/x
1.6003 = 15/x
x = 9.373 m
