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nikklg [1K]
3 years ago
7

Easton won Best in Show in 60% of the shows he entered. In how many shows was Easton entered if he won Best in Show 15 times las

t year?
Mathematics
1 answer:
pochemuha3 years ago
7 0
25 shows total. Hope this helps.
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If rhe discriminant of a quadratic equation is equal to -8 which statement describes the roots
Nastasia [14]

Answer:

Step-by-step explanation:

Given

Discriminant = -8

Required

Determine the type of roots

Represent Discriminant with D; such that

D = -8

D is calculated as thus

D = b^2 - 4ac

And it has the following sequence of results

When D > 0; then the roots of the quadratic equation are real but not equal

When D = 0; then the roots of the quadratic equation are real and equal

When D < 0; then the roots of the quadratic equation are complex or imaginary

Given that D = -8; This means that D < 0; and base on the above analysis, we can conclude that the roots of the quadratic equation are complex or imaginary

6 0
3 years ago
∫ (3x²-2)/x³ dx<br><br> help
pychu [463]
We will use integration by substitution, as well as the integrals
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⇒
d
u
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2
x
d
x
. Then
1
2
∫
(
x
2
+
1
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−
1
x
2
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x
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∫
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−
1
u
d
u
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1
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1
u
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d
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(
u
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|
u
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2
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Final answer
4 0
3 years ago
Find the simplified quotient. <br><br> y^2+y/y^2-2y/y^2-4y+4
BabaBlast [244]

Answer: y2-1/y-4y+4

if this helped please mark brainliest

7 0
3 years ago
How many eights make a half
evablogger [386]

Answer:

Four, because 4/8 = 1/2 There are obviously 8 1/8ths in a whole so half of that amount is obviously 4 1/8ths.

Step-by-step explanation:

Gave above.

7 0
3 years ago
FIND THE SUM OF 20 TERMS OF THE ARITHMETIC SERIES IN WHICH 3rd TERM IS 7 AND 7th TERM IS 2 MORE THAN THREE TIMES ITS 3rd TERM
algol13

Answer:

740

Step-by-step explanation:

The n th term of an arithmetic series is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₃ = 7 and a₇ = (3 × 7) + 2 = 21 + 2 = 23 , then

a₁ + 2d = 7 → (1)

a₁ + 6d = 23 → (2)

Subtract (1) from (2) term by term

4d = 16 ( divide both sides by 4 )

d = 4

Substitute d = 4 into (1)

a₁ + 2(4) = 7

a₁ + 8 = 7 ( subtract 8 from both sides )

a₁ = - 1

The sum to n terms of an arithmetic series is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ] , thus

S_{20} = \frac{20}{2} [ (2 × - 1) + (19 × 4) ]

     = 10(- 2 + 76) = 10 × 74 = 740

8 0
3 years ago
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