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2 years ago

7

s quadrilateral JKLM the result of a dilation of quadrilateral ABCD by a scale factor of 2? Why or why not?

1 answer:

Likurg_2 [28]2 years ago

4 0

If quadrilateral JKLM has given values, as well as quadrilateral ABCD, it can be concluded from the given values if JKLM is a result of a dilation of ABCD by a scale factor of 2. Dilation factor is used to scale up a given figure. If ABCD has measurements of 1, 2, 3, and 4. Then the measurements of JKLM should be 4, 8, 12, and 16.

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Determine the value of the variable in the product of powers.

aleksandrvk [35]

Answer:

<u><em>1. x = - 3</em></u>

<u><em>2. y = -9</em></u>

<u><em>3. n = 0</em></u>

<u><em></em></u>

Explanation:

The expressions are garbled. The correct expressions to determine the product of powers are:

1. What is the value of x in the product of powers $5^5\cdot 5^x=5^2$ ?

x =

2. What is the value of y in the product of $p^{-3}\cdot p^{-6}=p^y$ ?

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3. What is the value of n in th product of $9^2\cdot 9^{-7}\cdot 9^n=9^{-5}$ ?

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<h2>Solutions</h2>

<u />

<u>1. What is the value of x in the product of powers </u> $5^5\cdot 5^x=5^2$ <u> ?</u>

Apply the rule of the <em>product of powers with the same base</em> to the left side of the equality.

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$5^5\cdot5^x=5^{(5+x)}$

Now the power on the left side has the same base as the power on the right side, so the exponents are the same:

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<u />

<u>2. What is the value of y in the product of </u> $p^{-3}\cdot p^{-6}=p^y$ <u> ?</u>

Again, the product of the two powers on the left side is equal to the common base raised to the sum of the exponents:

On the left side, you get:

$p^{-3}\cdot p^{-6}=p^{(-3-6)}=p^{-9}$

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Left side equal to right side:

$9^{(-5+n)}=9^{-5}\\\\-5+n=-5\\\\n=-5+5\\\\n=0$

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