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OverLord2011 [107]
3 years ago
5

Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distribute

d with a
mean of 100 and a standard deviation of 15.
n
f0 and
102
130
are
The area of the shaded region is (Round to four decimal places as needed.)
sions
Kented in
V3 and
andomly
d by in-
on affect
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Enter your answer in the answer box and then click Check Answer.
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Mathematics
1 answer:
jeyben [28]3 years ago
3 0

Answer: 0.4255

Step-by-step explanation:

Given:  IQ scores of adults, and those scores are normally distributed

Mean: \mu=100

Standard deviation: \sigma= 15

Let X denotes the IQ of a random adults.

The area between 102 and 130 = P(102

=P(0.13

Hence, area between 102 and 130 = 0.4255

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Assume that X is normally distributed with a mean of 20 and a standard deviation of 2. Determine the following. (a) P(X 24) (b)
Tems11 [23]

Answer:

a) P( X < 24 ) =  0.9772

b) P ( X > 18 ) =0.8413

c) P ( 14 < X < 26) = 0.9973

d)  P ( 14 < X < 26)  = 0.9973

e) P ( 16 < X < 20)  = 0.4772

f) P ( 20 < X < 26)  =  0.4987

Step-by-step explanation:

Given:

- Mean of the distribution u = 20

- standard deviation sigma = 2

Find:

a. P ( X  < 24 )

b. P ( X  > 18 )

c. P ( 18 < X  < 22 )

d. P ( 14 < X  < 26 )

e. P ( 16 < X  < 20 )

f. P ( 20 < X  < 26 )

Solution:

- We will declare a random variable X that follows a normal distribution

                                   X ~ N ( 20 , 2 )

- After defining our variable X follows a normal distribution. We can compute the probabilities as follows:

a) P ( X < 24 ) ?

- Compute the Z-score value as follows:

                                   Z = (24 - 20) / 2 = 2

- Now use the Z-score tables and look for z = 2:

                                   P( X < 24 ) = P ( Z < 2) = 0.9772

b) P ( X > 18 ) ?

- Compute the Z-score values as follows:

                                   Z = (18 - 20) / 2 = -1

- Now use the Z-score tables and look for Z = -1:

                    P ( X > 18 ) = P ( Z > -1) = 0.8413

c) P ( 18 < X < 22) ?

- Compute the Z-score values as follows:

                                   Z = (18 - 20) / 2 = -1

                                   Z = (22 - 20) / 2 = 1

- Now use the Z-score tables and look for z = -1 and z = 1:

                   P ( 18 < X < 22)  = P ( -1 < Z < 1) = 0.6827

d) P ( 14 < X < 26) ?

- Compute the Z-score values as follows:

                                   Z = (14 - 20) / 2 = -3

                                   Z = (26 - 20) / 2 = 3

- Now use the Z-score tables and look for z = -3 and z = 3:

                   P ( 14 < X < 26)  = P ( -3 < Z < 3) = 0.9973

e) P ( 16 < X < 20) ?

- Compute the Z-score values as follows:

                                   Z = (16 - 20) / 2 = -2

                                   Z = (20 - 20) / 2 = 0

- Now use the Z-score tables and look for z = -2 and z = 0:

                   P ( 16 < X < 20)  = P ( -2 < Z < 0) = 0.4772

f) P ( 20 < X < 26) ?

- Compute the Z-score values as follows:

                                   Z = (26 - 20) / 2 = 3

                                   Z = (20 - 20) / 2 = 0

- Now use the Z-score tables and look for z = 0 and z = 3:

                   P ( 20 < X < 26)  = P ( 0 < Z < 3) = 0.4987

8 0
4 years ago
What is the area of the figure?
son4ous [18]
Yes. 95 is correct.
You have three congruent "indentations" in the right hand side. Thus each section must be 15/3 = 5 cm long.
The top rectangle will be 8*5 = 40 cm^2
The bottom rectangle will also be 8*5 = 40 cm^2
The middle area will be 5(8-5) = 5 * 3 = 15 cm^2
40 + 40 + 15 = 95

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agasfer [191]

Answer:

e=-7

Step-by-step explanation:

3 0
3 years ago
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The width of a rectangle is 12 units. Can the perimeter x of the rectangle can be 60 units when its length y is 18 units? (1 poi
juin [17]

If the width is 12 and the length is 18, the perimeter of the rectangle is 12 + 12 + 18 + 18, or 60. So yes the perimeter can be 60.

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3 years ago
Which is NOT an example of an internal response to stimuli?
dezoksy [38]
D i think because stimuli is a responce right ?
7 0
4 years ago
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