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Ierofanga [76]
3 years ago
8

What is the behavior of?

Mathematics
2 answers:
lana [24]3 years ago
8 0

Answer:

option 1

Step-by-step explanation:

To determine the end behaviour we only need to look at the term of highest degree, that is the leading term in standard form.

• Even degree, negative leading coefficient

limit as x → ± ∞ = - ∞

Hence option 1

GarryVolchara [31]3 years ago
5 0

Answer:

i thin its option 1 or 2 because by looking at the problem it kinda click  after starring at it for awhile

i hope this useful in a way  

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What is the quotient of 3,600 ÷ 103?
Serga [27]

Answer:

34.95

Step-by-step explanation:

Look at the person above and give them credit

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3 years ago
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Which is an equation of a circle with center (2, −10) and radius 3
stepladder [879]
(x - a)^2 + (y - b)^2 = r^2 is a circle with centre at (a, b) and radius of r
The correct answer is (x - 2)^2 + (y + 10)^2 = 9 ie the first one
6 0
3 years ago
The probability that a certain make of car will need repairs in the first seven months is 0.9. A dealer sells three such cars. W
aleksandr82 [10.1K]

Answer:

0.9990 = 99.90% probability that at least one of them will require repairs in the first seven months.

Step-by-step explanation:

For each car, there are only two possible outcomes. Either they will require repair in the first seven months, or they will not. The probability of a car requiring repair in the first seven months is independent of other cars. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a certain make of car will need repairs in the first seven months is 0.9.

This means that p = 0.9A dealer sells three such cars.

A dealer sells three such cars.

This means that n = 3

What is the probability that at least one of them will require repairs in the first seven months?

Either none will require repairs, or at least one will. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X > 0) = 1

We want P(X > 0). So

P(X > 0) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.9)^{0}.(0.1)^{3} = 0.001

Then

P(X > 0) = 1 - P(X = 0) = 1 - 0.001 = 0.9990

0.9990 = 99.90% probability that at least one of them will require repairs in the first seven months.

4 0
3 years ago
A store sells a 3-pound bag of oranges for $3.60 and a 5-pound bag of oranges for $5.25. What is the difference between the pric
tigry1 [53]

The difference between the price per pound for the three pound bag of oranges and the price per pound for the 5 lb bag of oranges is $0.15

Given

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Price of 5lb bag = $5.25

We have to calculate the per pound price for each bag to compare the per pound price for both

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Price of one pound in 5lb bag-

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Difference between the prices-

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The difference between the price per pound for the three pound bag of oranges and the price per pound for the 5 lb bag of oranges is $0.15

8 0
3 years ago
Select the equivalent expression . (2^ -4 * z^ -3 )^ 5 =?
Travka [436]

Step-by-step explanation:

The option is C

= 1/ 2^20 • z^15

Hope it will help :)

8 0
3 years ago
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