Answer:
80mm
Step by step explanation:
To convert centimeters to millimeters, all you have to do is multiply the number of centimeters by 10.
A) See picture for the table.
To make the table, multiply 47774 by 1.5% to get total that have diabetes and multiply 5855 by 2.5% to get total unemployed that have it, then using subtraction fill in the other squares of the table.
B)
Hypothesis:
H0: No association between employment and diabetes.
H1: Association between the two
Using a graphing calculator or Excel, run a chi-test.
Chi squared equals 31.844 with 1 degrees of freedom.
The two-tailed P value is less than 0.0001
With this information we can reject the null hypothesis and conclude there is an association between diabetes and employment.
C)
Although there is a statistical significance, there really is no practical significance between an incidence rate of 1.5 or 2.5%
We want the final coordinate of K to become (-3,1). If you reflect across the y-axis, you transform

So, we need to move K to (3,1), and then reflect it across the y-axis. Since K starts at (-1,4), we have to move it 4 units to the right and 3 units down.
a. Answer: D: (∞, ∞)
R: (-∞, ∞)
<u>Step-by-step explanation:</u>
Theoretical domain is the domain of the equation (without an understanding of what the x-variable represents).
Theoretical range is the range of the equation given the domain.
c(p) = 25p
There are no restrictions on the p so the theoretical domain is All Real Numbers.
Multiplying 25 by All Real Numbers results in the range being All Real Numbers.
a) D: (∞, ∞)
R: (-∞, ∞)
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b. Answer: D: (0, 200)
R: (0, 5000)
<u>Step-by-step explanation:</u>
Practical domain is the domain of the equation WITH an understanding of what the x-variable represents.
Practical range is the range of the equation given the practical values of the domain.
The problem states that p represents the number of cups. Since we can't have a negative amount of cups, p ≥ 0. The problem also states that Bonnie will purchase a maximum of 200 cups. So, 0 ≤ p ≤ 200
The range is 25p → (25)0 ≤ (25)p ≤ (25)200
→ 0 ≤ 25p ≤ 5000
b) D: (0, 200)
R: (0, 5000)