This should be easy because we just have to use substitution method. Substitute the value of x from the second equation into the x of the first equation.
-4(2y) + 11y = 15
-8y + 11y = 15
3y = 15 ; y = 5
Substitute this value of y to either the first or second equation.
x = 2(5) = 10
The ordered pair is therefore (10,5).
we know that
For a polynomial, if
x=a is a zero of the function, then
(x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.
So
In this problem
If the cubic polynomial function has zeroes at 2, 3, and 5
then
the factors are

Part a) Can any of the roots have multiplicity?
The answer is No
If a cubic polynomial function has three different zeroes
then
the multiplicity of each factor is one
For instance, the cubic polynomial function has the zeroes

each occurring once.
Part b) How can you find a function that has these roots?
To find the cubic polynomial function multiply the factors and equate to zero
so

therefore
the answer Part b) is
the cubic polynomial function is equal to

Answer:
4
Step-by-step explanation:
Answer:
x y
7 4
2 3
7 5
Step-by-step explanation:
it cant be a function if it has two of the same domains.
In order to find the y-intercept, replace x by 0.
So, for first option:
f(0) = 7(1) - 2 = 5
For second option:
f(0) = -3(1) - 5 = -8
For third option:
f(0) = 5(1)-1=4
For Fourth option:
f(0) = -5(1) + 10 = 5
For Fifth Option:
f(0) = 2(1) + 5 = 7
So, option 1 and 4 have the y-intercept (0,5)